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FromTheMoon [43]
3 years ago
15

14. Which commercial RDBMS product was the first to hit the market and is the biggest?

Computers and Technology
1 answer:
schepotkina [342]3 years ago
3 0

The answer is definitely (A. SQL server) it was released back in 2010 and is huge!

Let us know if there is anything else you need to know.

Mark brainlest :)

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You have recently implemented a new WAN technology to connect a remote branch office to your headquarters. While making VoIP cal
sergejj [24]

Answer:

Satellite is the correct answer to the given question .

Explanation:

Connections via the  satellite deliver the communication in the whole  world environment .The  reliability, expense and the performance problems have long suffered satellite connections, rendering the satellite-based WAN connections are just under the suitable.

The satellite wan connection is the Linking of  the head office to a remote branch office.The satellite wan technology  allowing the VoIP calls between both the departments .When the workers complain about discrepancies between something talking as well as the other person learning.

5 0
3 years ago
Brainless is one the way if you help
V125BC [204]

Answer:

1. x - 6

2. p - ? = 7

i chose these equations because

a number - 6 = the weight of your backpack.

p - an unknown number without a substitute variable = slices of bread left.

3 0
2 years ago
Overcoming the fundamental attribution error requires making an effort to shift an external attribution into an internal attribu
Irina-Kira [14]

The correct answer on Edgen is:

(B.) False

I just took the test and this is the right answer.

8 0
3 years ago
Read 2 more answers
In reference to for-each loops, which of the following statements is true? f
Artemon [7]

In computer programming, the for each loop is called enhanced for each loop.

It is the shorter version of the traditional for loop used in computer programming.

The enhanced for loop is written as shown.

For ( data type variable : array_name )

{

code of the loop goes here

}

An example of integer array using enhanced for loop is shown below. The Java code is given below.

1. First, an integer array is declared and initialized simultaneously. Hence, the size of the array is not known explicitly and no index variable is needed.

2. Next, an integer variable is initialized which iterates over every element of the array.

3. The variable which holds the element of the array is displayed.

int[] tens = { 10, 20, 30, 40, 50, 60, 70, 80, 90 } ;

for ( int t : tens )

{

System.out.println( t );

}  

a.  The above code does not include any index variable. The enhanced loop can only be used to traverse the given array.

The array can only be traversed in forward direction, i.e., elements of the array can only be traversed beginning from the first element to the last.

By default, enhanced for loop traversal begins from index 0 of the array to the last index of the array. This needs the index variable to be coded.

Also, index variable gives traditional for loop more control on how the elements can be traversed and which elements to be traversed.

b.  The for each loop can not always be re written as for loop. The for loop is used when more just element traversal is needed.

c.  The for each loop executes only till the variable traverses through all the elements of the array. The loop terminates when all the elements are visited.  Thus, ArrayIndexOutOfBoundsException can not be thrown by the enhanced for loop.

4 0
2 years ago
Read 2 more answers
Assume a computer that has 32-bit integers. Show how each of the following values would be stored sequentially in memory, starti
finlep [7]

Answer:

Adresses                          Big endian                                    Little Endian

0x100                                  AB                                                 56

0x101                                   12                                                  34

0x102                                  34                                                  12

0x103                                  56                                                 AB

0x104                                  00                                                 76

0x105                                  2B                                                 F8

0x106                                  F8                                                 2B

0x107                                 76                                                 00

0x108                                00                                                 A1

0x109                                08                                                B0  

0x10A                                B0                                                08

0x10B                                A1                                                 00

0x10C                               00                                                  01

0x10D                               00                                                 00  

0x10E                               00                                                  00

0x10F                                01                                                   00

0x110                                FE                                                   34

0x111                                 DC                                                  12

0x112                                12                                                    DC  

0x113                                34                                                   FE

Explanation:

As, it is mentioned that all the integers have 32 bits and all the data given in the question is in Hexadecimal. In Hexadecimal each number consists of 4 bits.

Each memory location contains 1 byte = 8 bits of data. So we store 2 digits of Hexadecimal number each location from each number in given data. If any number contains less than 32 bits in binary, we will add zeros to complete the number in 32 bits.

In big endian order, data is stored from upper most bit to lower most bit in sequential order and in Little Endian order it is vise versa.

6 0
2 years ago
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