E=1/2mv^2 solve for m

Mathematics

1 answer:

VikaD [51]3 years ago

3 0

There isn't enough info to do so.

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To verify the identity tan (x1+x2+x3) = tan x1 + tan x2 + tan x3 - tan x1 tan x2 tan x3 / 1 - tan x1 tan x2 - tan x2 tan x3

andrezito [222]

Answer:

The answer is the last one

$tan(x_{1}+x_{2}+x_{3})=\frac{tanx_{1}+tan(x_{2}+x_{3})}{1-tanx_{1}tan(x_{2}+x_{3})}$

Step-by-step explanation:

∵ $tan(x_{1}+x_{2}+x_{3}=\frac{tanx_{1}+tan(x_{2}+x_{3})}{1-tanx_{1}tan(x_{2}+x_{3})}$

$=\frac{tanx_{1}+\frac{tanx_{2}+tanx_{3}}{1-tanx_{2}tanx_{3}} }{1-tanx_{1}(\frac{tanx_{2}+tanx_{3}}{1-tanx_{2}tanx_{3}})}$

Multiply up and down by $1-tanx_{2}tanx_{3}$

$\frac{tanx_{1}(1-tanx_{2}tanx_{3})+tanx_{2}+tanx_{3}}{1-tanx_{2}tanx_{3}-tanx_{1}tanx_{2}-tanx_{1}tanx_{3}}$

$=\frac{tanx_{1}+tanx_{2}+tanx_{3}-tanx_{1}tanx_{2}tanx_{3}}{1-tanx_{1}tanx_{2}-tanx_{2}tanx_{3}-tanx_{1}tanx_{3}}$

7 0

3 years ago

Read 2 more answers

Just say answer, no need to explain! Thanks!

GaryK [48]

The given function is

f(x) = |x|

Moving 4 units to right means, subtracting the number from x. So moving |x| 4 units to right will give:

f(x) = |x-4|

Moving 2 units up means addition of a number to the function. So moving 2 units up will give:

f(x) = |x-4| + 2

Thus, the correct answer to the question is option B

6 0

4 years ago

Randy divides (2x4 – 3x3 – 3x2 + 7x – 3) by (x2 – 2x + 1) as shown below. What error does Randy make?

jarptica [38.1K]

error is in constant term of quotient