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Ipatiy [6.2K]
3 years ago
9

The perimeter of a rectangle is 300 feet. The width of the rectangle is 10 feet more than the length. What is the width of the r

ectangle? A) 50 feet B) 60 feet C) 70 feet D) 80 feet
Mathematics
1 answer:
gavmur [86]3 years ago
7 0
300 = 2(x + x + 10)
300 = 2(2x +10)
300 = 4x + 20
4x = 280
x = 70
x + 10 = 80
width = 80ft
answer <span>D) 80 feet</span>
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an umbrella is made by stitching 10 triangular pieces of cloth of two different colours where each pieces measuring 48cm,48cm,an
mars1129 [50]

Answer:

Step-by-step explanation:

first we need to calculate the area of isosceles triangle having sides 48cm, 48cm and 30cm

a = 48

b= 30

Area of isosceles triangle using only sides = ½[√(a^2 − b^2 /4) × b]

= 1/2*30√( 48² - 1/4×30²)

=1/2*30√ (2304 -225)

=684sq cm

cost required to make umbrella= 10*684*5

= 3<em>4200</em>

7 0
3 years ago
Question is in the pic<br><br> pls include step by step if possible
Rama09 [41]

Answer:

34

Step-by-step explanation:

(x + 12) + 100 + x = 180

2x + 112 = 180

2x = 68

x = 34

6 0
2 years ago
A huge ice glacier in the Himalayas initially covered an area of 454545 square kilometers. Because of changing weather patterns,
guajiro [1.7K]

We have been given that a huge ice glacier in the Himalayas initially covered an area of 45 square kilo-meters. The relationship between A, the area of the glacier in square kilo-meters, and t, the number of years the glacier has been melting, is modeled by the equation A=45e^{-0.05t}.

To find the time it will take for the area of the glacier to decrease to 15 square kilo-meters, we will equate A=15 and solve for t as:

15=45e^{-0.05t}

\frac{15}{45}=\frac{45e^{-0.05t}}{45}

\frac{1}{3}=e^{-0.05t}

Now we will switch sides:

e^{-0.05t}=\frac{1}{3}

Let us take natural log on both sides of equation.

\text{ln}(e^{-0.05t})=\text{ln}(\frac{1}{3})

Using natural log property \text{ln}(a^b)=b\cdot \text{ln}(a), we will get:

-0.05t\cdot \text{ln}(e)=\text{ln}(\frac{1}{3})

-0.05t\cdot (1)=\text{ln}(\frac{1}{3})

-0.05t=\text{ln}(\frac{1}{3})

t=\frac{\text{ln}(\frac{1}{3})}{-0.05}

t=\frac{\text{ln}(\frac{1}{3})\cdot 100}{-0.05\cdot 100}

t=\frac{\text{ln}(\frac{1}{3})\cdot 100}{-5}

t=-\text{ln}(\frac{1}{3})\cdot 20

t=-(\text{ln}(1)-\text{ln}(3))\cdot 20

t=-(0-\text{ln}(3))\cdot 20

t=20\text{ln}(3)

Therefore, it will take 20\text{ln}(3) years for area of the glacier to decrease to 15 square kilo-meters.

6 0
3 years ago
I need the answers to it please. I'll give 36 points
nadya68 [22]

1st question

make line plot similar to the second.  above 1/6 put 6 x's; above 1/3 put 3 x's; above 1/2 put 6 x's.

average:  1/3




7 0
3 years ago
HELP QUICK PLSSSSS ILL GIVE LOTS OF POINTS
mariarad [96]

Answer:

B - $41,500

Step-by-step explanation:

After Subtracting his liabilities this is what I got.

Hope this Helps!

:D

6 0
3 years ago
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