Rational because 5^3
irrational
The solution would be like
this for this specific problem:
Given: 40
km/h
2 km
t = d / v
t = 2 km / 40 km/h
t = 0.05 h * 60 minutes = 3 minutes
<span>At
this rate, it would take 3 minutes for the red kangaroo to jump 2 km.</span>
Answer:
Area of circle A =113.14 mm²
Area of circle b = 314.29 mm²
Area of circle C = 452.57 mm²
Area of circle A = 254.57 mm²
2.25 times
Step-by-step explanation:
Area of a circle = nr²
where n = 22/7
r = radius
Circle A's radius = 6mm
Circle B's radius = 6mm + 4mm = 10mm
Circle C's radius = 10mm + 2mm = 12mm
Circle D's radius = 12mm - 3mm = 9mm
Area of circle A = (22/7) x 6² = 113.14 mm²
Area of circle b = (22/7) x 10² = 314.29 mm²
Area of circle C = (22/7) x 12² = 452.57 mm²
Area of circle A = (22/7) x 9² = 254.57 mm²
Number of times the area of circle D is greater than that circle A = Area of circle D / Area of circle A
254.57 mm² / 113.14 mm² = 2.25 times
Answer:
The number of trucks and sedans can be
(0 trucks ,26 sedans)
(8 trucks ,21 sedans)
(24 trucks ,11 sedans)
(25 trucks ,1 sedans)
(32 trucks ,6 sedans)
(16 trucks ,16 sedans)
Step-by-step explanation:
Given:
The cost for trucks =$5
The cost for sedans =$8
The total amount collected = $208
To Find:
Number of trucks and sedans passed through the toll booth =?
Solution:
Let the number of trucks be x and the number of sedans be y
Then
5x + 8y = 208-------------------------------(1)
By Trail and error method
5(0) + 8(26) = 208
5(8) + 8(21) = 208
5(24) +8(11) =208
5(25) + 8(1) = 208
5(32) + 8(6) =208
5(16) + 8(16) = 208