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3 years ago

Can someone help me with and and can you please write how you got it so I can understand

Mathematics

2 answers:

EastWind [94]3 years ago

8 0

Answer:

12x + 4

Step-by-step explanation:

ok so a rectangle has 4 sides, 2 of which are called lengths, and 2 of which are widths.

length = 2x-3

width = 4x+5

the perimenter is the total of the 4 sides.

2(2x-3) = 4x-6 (the total for lengths)

2(4x+5) = 8x+10 (the total for widths)

add the 2 together:

12x+4

vekshin13 years ago

3 0

Answer:

2(2x - 3) + 2(4x + 5)= OR 12x + 4

Step-by-step explanation:

First, we need to know the formula of calculating the perimeter

The formula is 2(Length) + 2(Width) = Perimeter

The length is 2x - 3

The width is 4x + 5

Now fill in the known dimensions in the formula

2(2x - 3) + 2(4x + 5)= perimeter

This expression can be used to represent the perimeter of Rectangle ABCD, though (depending on the teacher) it is not simplified.

We remove the brackets by multiplying the number that's outside the brackets by the numbers or figures inside.

hence, 4x - 6 + 8x +10 = the perimeter

Note: A negative multiplied by a negative equals a positive. A positive multiplied by a negative and vice versa equals a negative. A positive multiplied by a positive equals a positive.

We can now simplify further by adding like terms. i.e, x + x, and integers + integers.

4x + 8x - 6 + 10 = the perimeter

12x + 4 = the perimeter

The perimeter can be represented by the expression, 12x + 4

Or (depending on the teacher,) 2(2x - 3) + 2(4x + 5)=

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Shkiper50 [21]

Answer:

$x=1$

Step-by-step explanation:

$~~~~~x = \dfrac{1}{2 - \dfrac 1{2-\dfrac{1}{2-x}}}\\\\\\\implies x = \dfrac{1}{2 - \dfrac 1{\dfrac{4-2x-1}{2-x}}}\\\\\\\implies x= \dfrac{1}{2 - \dfrac{2-x}{3-2x}}\\\\\\\implies x = \dfrac{1}{\dfrac{6-4x-2+x}{3-2x}}\\\\\\\implies x = \dfrac{3-2x}{4-3x}\\\\\\\implies 4x -3x^2 = 3-2x\\\\\\\implies 3x^2 -4x +3-2x = 0\\\\\\\implies 3x^2 -6x +3 = 0\\\\\\\implies 3(x^2 -2x +1) =0\\\\\\\implies x^2 -2x +1 = 0\\\\\\\implies (x-1)^2 = 0\\\\\\\implies x -1 = 0\\\\\\\implies x = 1$

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2 years ago

Please answer and explain how you did it.

alukav5142 [94]

Refer to the attached image.

Given: $m \angle A = 65^\circ$ and measure of exterior angle at C = $117^\circ$ .

We have to determine the measure of angle B and angle BCA.

By applying exterior angle property of the triangle which states:

"An exterior angle of a triangle is equal to the sum of the opposite interior angles".

So, exterior angle C = $m \angle A + m \angle B$

$117^\circ = 65^\circ+ m \angle B$

$m \angle B = 52^\circ$

Now, applying angle sum property in triangle ABC which states:

"The sum of all the angles of a triangle is 180 degrees".

$m \angle A + m \angle B + m \angle BCA = 180^\circ$

$65^\circ + 52^\circ + m \angle BCA = 180^\circ$

$117^\circ + m \angle BCA = 180^\circ$

$m \angle BCA = 180^\circ - 117^\circ$

$m \angle BCA =63^\circ$

Therefore, the measure of $m \angle B = 52^\circ$ and $m \angle BCA =63^\circ$ .

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Tresset [83]

Answer:

Step-by-step explanation:

its c

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2 years ago

Which number is equivalent to 2^−5⋅ 3 ⋅ 2^2 ⋅ 3^3? A. 648 B. 216 C. 81/8 D. 27/8

sesenic [268]

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