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Korvikt [17]
4 years ago
6

I need help understanding it

Mathematics
1 answer:
dezoksy [38]4 years ago
4 0

so the table is saying how each person gets x bottles in one day. for example it says each athlete drinks 4 bottles of water, each coach drinks 3 bottles of water, and each judge drinks 2 bottles of water.

so each athlete drinks 12 bottles total, each coach drinks 9 bottles total, and each judge drinks 6 bottles total in those 3 days. then you multiply those numbers by the total of each.

12×117 = 1404

9×7 = 63

6×4 = 24

1491

Add them and thats how many bottles you will need. since each case holds 24 bottles you dived the total of bottles by 24, round and you get how many cases you need.

1491÷24 = 62.125

63

your answer is 63

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which equation has infinitely many solutions equation 1: 3g + 24 = 3(g + 8) equation 2: 5c + 9 = 5c - 12
xeze [42]
Let's solve each equation. If we end up with something like x = 5, then we know we have one solution. If we end up with something like 3 = 3, then we have infinitely many solutions.

Equation 1:
3g + 24 = 3(g + 8)

Use the distributive property, which states: a(b+c) = ab + ac

3g + 24 = 3g + 3(8)
3g + 24 = 3g + 24

Subtract 3g on both sides

24 = 24

This means that equation 1 has infinitely many solutions.

Just to be sure, let's make sure that equation 2 doesn't have infinitely many solutions also.

Equation 2:
5c + 9 = 5c - 12

Subtract 5c on both sides

9 = -12

Now, this statement is false. This means that equation 2 has no solutions.

Your final answer is: Equation 1 has infinitely many solutions.
3 0
3 years ago
Order the set of decimals from least to greatest. 0.503, 0.53, 0.529
Feliz [49]
0.503, 0.529, 0.53 would be the answer
7 0
3 years ago
Read 2 more answers
2.Sketch the region whose area is given by the integral and evaluate the integral.
boyakko [2]

2. The integration region,

\left\{(r,\theta)\mid\dfrac\pi6\le\theta\le\dfrac\pi2\land2\le r\le3\right\}

corresponds to what you might call an "annular sector" (i.e. the analog of circular sector for the annulus or ring). In other words, it's the region between the two circles of radii r=2 and r=3, taken between the rays \theta=\frac\pi6 and \theta=\frac\pi2. (The previous question of yours that I just posted an answer to has a similar region with slightly different parameters.)

You can separate the variables to compute the integral:

\displaystyle\int_{\pi/6}^{\pi/2}\int_2^3r^2\sin^2\theta\,\mathrm dr\,\mathrm d\theta=\left(\int_{\pi/6}^{\pi/2}\sin^2\theta\,\mathrm d\theta\right)\left(\int_2^3r^2\,\mathrm dr\right)

which should be doable for you. You would find it has a value of 19/72*(3√3 + 4π).

3. Without knowing the definition of the region <em>D</em>, the best we can do is convert what we can to polar coordinates. Namely,

r^2=x^2+y^2

so that

\displaystyle\iint_De^{x^2+y^2}\,\mathrm dA=\iint_Dre^{r^2}\,\mathrm dr\,\mathrm d\theta

7 0
3 years ago
Round 241,639 to the nearest thousand.
ser-zykov [4K]
242,000 i think
hope this helped
3 0
3 years ago
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How can I turn this into a graph in Desmos,
velikii [3]

Answer:

in Desmos there should be a plus sign right above the list of your equations on the left side. Click that plus sign and then click "table". then enter your numbers. then your points will be shown on the graph

to turn this into a line long press on the button next "y" on the table you have made, then select "lines"

8 0
4 years ago
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