Well, if you do this in reverse
23+17 = 40
40-23 = 17
40 would be your answer.
Answer:
$238.33
Step-by-step explanation:
We have been given that Lan pays a semiannual premium of $450 for automobile insurance, a monthly premium of $130 for health insurance, and an annual premium of $400 for life insurance.
First of all, we will find annual costs of each insurance.
![\text{Yearly automobile insurance}=2\times \$450](https://tex.z-dn.net/?f=%5Ctext%7BYearly%20automobile%20insurance%7D%3D2%5Ctimes%20%5C%24450)
![\text{Yearly automobile insurance}=\$900](https://tex.z-dn.net/?f=%5Ctext%7BYearly%20automobile%20insurance%7D%3D%5C%24900)
![\text{Yearly health insurance}=12\times \$130](https://tex.z-dn.net/?f=%5Ctext%7BYearly%20health%20insurance%7D%3D12%5Ctimes%20%5C%24130)
![\text{Yearly health insurance}=\$1560](https://tex.z-dn.net/?f=%5Ctext%7BYearly%20health%20insurance%7D%3D%5C%241560)
![\text{Yearly life insurance}=1\times \$400](https://tex.z-dn.net/?f=%5Ctext%7BYearly%20life%20insurance%7D%3D1%5Ctimes%20%5C%24400)
![\text{Yearly life insurance}=\$400](https://tex.z-dn.net/?f=%5Ctext%7BYearly%20life%20insurance%7D%3D%5C%24400)
![\text{Total yearly expenses}=\$900+\$1560+\$400](https://tex.z-dn.net/?f=%5Ctext%7BTotal%20yearly%20expenses%7D%3D%5C%24900%2B%5C%241560%2B%5C%24400)
![\text{Total yearly expenses}=\$2860](https://tex.z-dn.net/?f=%5Ctext%7BTotal%20yearly%20expenses%7D%3D%5C%242860)
Now, we will divide total yearly cost by 12 to find monthly expenses.
![\text{Monthly expenses}=\frac{\$2860}{12}](https://tex.z-dn.net/?f=%5Ctext%7BMonthly%20expenses%7D%3D%5Cfrac%7B%5C%242860%7D%7B12%7D)
![\text{Monthly expenses}=\$238.33333](https://tex.z-dn.net/?f=%5Ctext%7BMonthly%20expenses%7D%3D%5C%24238.33333)
![\text{Monthly expenses}\approx \$238.33](https://tex.z-dn.net/?f=%5Ctext%7BMonthly%20expenses%7D%5Capprox%20%5C%24238.33)
Therefore, the monthly expenses would be $238.33.
The answer to this is 200,000.
Answer:
Go on to photo math it's good for equations
<h3>The volume of a container with a radius of 4 centimeters and a height of 4 centimeters is 67.2 cubic centimeter</h3>
<em><u>Solution:</u></em>
<em><u>The volume of a container varies jointly with the square of its radius, r, and its height, h
</u></em>
Therefore,
![v \propto r^2h\\\\v = k \times r^2h ----------- eqn\ 1](https://tex.z-dn.net/?f=v%20%5Cpropto%20r%5E2h%5C%5C%5C%5Cv%20%3D%20k%20%5Ctimes%20r%5E2h%20-----------%20eqn%5C%201)
<em><u>The container has a height of 10 centimeters, and radius of 6 centimeters, and a volume of 377 cubic centimeters
</u></em>
<em><u>
Substitute v = 377 and h = 10 and r = 6 in eqn 1</u></em>
![377 = k \times 6^2 \times 10\\\\377 = 360 \times k\\\\k = \frac{377}{360}\\\\k = 1.047 \approx 1.05](https://tex.z-dn.net/?f=377%20%3D%20k%20%5Ctimes%206%5E2%20%5Ctimes%2010%5C%5C%5C%5C377%20%3D%20360%20%5Ctimes%20k%5C%5C%5C%5Ck%20%3D%20%5Cfrac%7B377%7D%7B360%7D%5C%5C%5C%5Ck%20%3D%201.047%20%5Capprox%201.05)
<em><u>What is the volume of a container with a radius of 4 centimeters and a height of 4 centimeters?</u></em>
<em><u>Substitute k = 1.05 and r = 4 and h = 4 in eqn 1</u></em>
![v = 1.05 \times 4^2 \times 4\\\\v = 1.05 \times 16 \times 4\\\\v = 67.2](https://tex.z-dn.net/?f=v%20%3D%201.05%20%5Ctimes%204%5E2%20%5Ctimes%204%5C%5C%5C%5Cv%20%3D%201.05%20%5Ctimes%2016%20%5Ctimes%204%5C%5C%5C%5Cv%20%3D%2067.2)
Thus volume of a container with a radius of 4 centimeters and a height of 4 centimeters is 67.2 cubic centimeter