Complete question is:
Seventy million pounds of trout are grown in the U.S. every year. Farm-raised trout contain an average of 32 grams of fat per pound, with a standard deviation of 7 grams of fat per pound. A random sample of 34 farm-raised trout is selected. The mean fat content for the sample is 29.7 grams per pound. Find the probability of observing a sample mean of 29.7 grams of fat per pound or less in a random sample of 34 farm-raised trout. Carry your intermediate computations to at least four decimal places. Round your answer to at least three decimal places.
Answer:
Probability = 0.0277
Step-by-step explanation:
We are given;
Mean: μ = 32
Standard deviation;σ = 7
Random sample number; n = 34
To solve this question, we would use the equation z = (x - μ)/(σ/√n) to find the z value that corresponds to 29.7 grams of fat.
Thus;
z = (29.7 - 32)/(7/√34)
Thus, z = -2.3/1.200490096
z = -1.9159
From the standard z table and confirming with z-calculator, the probability is 0.0277
Thus, the probability to select 34 fish whose average grams of fat per pound is less than 29.7 = 0.0277
Answer:
x = 14
Step-by-step explanation:
The angles with the measures (x+12) and (3x-16) are vertical, which makes their measures equal.
x+12 = 3x-16
On both sides, subtract 3x and subtract 12 to get this.
-2x = -28
Divide by -2.
x = 14
Answer: Option 'A' is correct.
Step-by-step explanation:
Since we have given that
Rational numbers are those numbers which can be written as p/q form or it must be non terminating but recurring number.
-13 can be written as p/q form as 
is a rational number because of its form.
81 can be written in p/q form as 
But √2 is non terminating and non recurring number.
Hence, √2 is not a rational number.
Therefore, Option 'A' is correct.
Answer:
A and c
Step-by-step explanation:
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