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Morgarella [4.7K]
3 years ago
10

Give the equation of a line in slope-intercept form with the following criteria:

Mathematics
1 answer:
Vsevolod [243]3 years ago
3 0

Answer:

y = - \frac{7}{6}x + 9

Step-by-step explanation:

We need to find a straight line that is perpendicular to the line y = \frac{6}{7} x + 4.

So, the slope of the given straight line is \frac{6}{7} {Since the equation is in slope-intercept form}

Now, the slope of the required straight line will be [tex]- \frac{7}{6}[/tex]

{Since, the product of slopes of two straight line that are perpendicular to each other is -1, and \frac{6}{7} \times (- \frac{7}{6}) = - 1}

Then the equation of the required straight line in slope-intercept form will be y = - \frac{7}{6} x + c ............. (1) {Where c is any constant}

Now, point (12, -5) will satisfy the equation (1).

Hence, -5 = - \frac{7}{6}(12) + c

⇒ - 5 = - 14 + c

⇒ c = 9

Therefore, the complete equation of the required straight line is y = - \frac{7}{6}x + 9 (Answer)

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