Answer:
e. The probability of observing a sample mean of 5.11 or less, or of 5.29 or more, is 0.018 if the true mean is 5.2.
Step-by-step explanation:
We have a two-tailed one sample t-test.
The null hypothesis claims that the pH is not significantly different from 5.2.
The alternative hypothesis is that the mean pH is significantly different from 5.2.
The sample mean pH is 5.11, with a sample size of n=50.
The P-value of the test is 0.018.
This P-value corresponds to the probability of observing a sample mean of 5.11 or less, given that the population is defined by the null hypothesis (mean=5.2).
As this test is two-tailed, it also includes the probability of the other tail. That is the probability of observing a sample with mean 5.29 or more (0.09 or more from the population mean).
Then, we can say that, if the true mean is 5.2, there is a probability P=0.018 of observing a sample of size n=50 with a sample mean with a difference bigger than 0.09 from the population mean of the null hypothesis (5.11 or less or 5.29 or more).
The right answer is e.
Answer:
(-3,-4)
Step-by-step explanation:
Step-by-step explanation:
We have been given that AE=BE and 
.
We can see that angle CEA is vertical angle of angle DEB, therefore, 
as vertical angles are congruent.
We can see in triangles CEA and DEF that two angles and included sides are congruent.
or 
Therefore, 
by ASA postulate.
Since corresponding parts of congruent triangles are congruent, therefore CE must be congruent to DE.
Answer:
See attachment
Step-by-step explanation:
We want to graph the line with slope
and y-intercept ,
The equation of this line is
Starting at -7 on the y-axis, we run 5 units and rise 2 units right.
Then draw a line through the y intercept and the new point
The graph is shown in the attachment.
If that is a rhombus as it says it is, then the diagonals are perpendicular to one another, meaning where they meet, they form right angles. Therefore, angle x is a 90 degree angle.
