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kkurt [141]
3 years ago
10

**************************** URGENT NEED OF HELP ****************************

Mathematics
1 answer:
muminat3 years ago
8 0

Answer:

i would say (B) or (C) but ill go with (C)

Step-by-step explanation:

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Tomika uses 6 inches of wire to make a necklace and 3 inches of wire to make a bracelet.
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3

Step-by-step explanation:

3x(6+3)=27, shed have 1 inch left over

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I WILL GIVE BRAINLEIST PLS HELP
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the answer is $65

Step-by-step explanation:

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What’s the least common denominator of 3/4 4/5 and 2/3
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✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

                  Hello!

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

❖ The least common denominator of 3/4 4/5 and 2/3 is 60.

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Solve for x.<br><br> y=4(x-7)<br><br> x=
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Answer:

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3 years ago
If t follows a t7 distribution, find t0 such that (a) p(|t | &lt; t0) = .9 and (b) p(t &gt; t0) = .05.
Thepotemich [5.8K]

Answer:

a) P(-t_o < t_7

Using the symmetrical property we can write this like this:

1-2P(t_7

We can solve for the probability like this:

2P(t_7

P(t_7

And we can find the value using the following excel code: "=T.INV(0.05,7)"

So on this case the answer would be t_o =\pm 1.895

b) For this case we can use the complement rule and we got:

1-P(t_7

We can solve for the probability and we got:

P(t_7

And we can use the following excel code to find the value"=T.INV(0.95;7)"

And the answer would be t_o = 1.895

Step-by-step explanation:

Previous concepts

The t distribution (Student’s t-distribution) is a "probability distribution that is used to estimate population parameters when the sample size is small (n<30) or when the population variance is unknown".

The shape of the t distribution is determined by its degrees of freedom and when the degrees of freedom increase the t distirbution becomes a normal distribution approximately.  

The degrees of freedom represent "the number of independent observations in a set of data. For example if we estimate a mean score from a single sample, the number of independent observations would be equal to the sample size minus one."

Solution to the problem

For this case we know that t \sim t(df=7)

And we want to find:

Part a

P(|t|

We can rewrite the expression using properties for the absolute value like this:

P(-t_o < t_7

Using the symmetrical property we can write this like this:

1-2P(t_7

We can solve for the probability like this:

2P(t_7

P(t_7

And we can find the value using the following excel code: "=T.INV(0.05,7)"

So on this case the answer would be t_o =\pm 1.895

Part b

P(t>t_o) =0.05

For this case we can use the complement rule and we got:

1-P(t_7

We can solve for the probability and we got:

P(t_7

And we can use the following excel code to find the value"=T.INV(0.95;7)"

And the answer would be t_o = 1.895

5 0
3 years ago
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