Answer:
A) 7,950$, B) 7,963.73$, C) Since daily interest means that 6%/365 of 7500 will be added and compounded every day for the given amount of time(in this case, one year), while annual interest means that 6% of 7500 will be added and compounded yearly for the given amount of time(I'm this case, one year).
Step-by-step explanation:
Given the compound interest formula, A = P(1+r/n)^nt, where A = total amount(final amount), P = principle or amount of money deposited(starting amount), r = annual interest rate(percent interest in respect to t ; decimal = %/100), and n = conversion rate(number of times compounded per t; how much is it compounded)
t = time(time in respect to years ; how long it is compounded).
For A) A = 7500( 1 + 6%/365 ) ^ 365 = 7500(1 + 0.06/365) ^365 = 7500(1 + 0.00016438356..)^365= 7500(≈1.0001644^365) = 7500(100.01644%^365) = 7500(≈106.183%) = 7963.725 ≈ 7963.73$
For B) A = 7500( 1 + 6% ) ^ 1 = 7500(1 + 0.06) = 7500(1.06) = 7500(106%) = 7950$
C) this is because compounding something with a higher frequency leads to a different percentage (as n approaches infinity with time proportional to the annual rate, the ratio between the principle and total amount are proportional to e)
If you mean <span>2x3(5x3 − 7)
2x3(15-7)
2x3(8)
6(8)
48
if you mean 2x^3(5x^3-7)
</span>2x^3(5x^3) - 2x^3(7)
10x^6-14x^3
Answer: C. (2, -4)
Step-by-step explanation:
Take into consideration that y is less than or equal to -2. The only option in which the y value is less than or equal to -2 is option C., thus C would correctly solve the system of inequalities.
Answer:
2nd Option: 2sec²Ѳ
Step-by-step explanation:
Please see the attached pictures for full solution.
Supposing a normal distribution, we find that:
The diameter of the smallest tree that is an outlier is of 16.36 inches.
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We suppose that tree diameters are normally distributed with <u>mean 8.8 inches and standard deviation 2.8 inches.</u>
<u />
In a normal distribution with mean
and standard deviation
, the z-score of a measure X is given by:
- The Z-score measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.<u>
</u>
<u />
In this problem:
- Mean of 8.8 inches, thus
. - Standard deviation of 2.8 inches, thus
.
<u />
The interquartile range(IQR) is the difference between the 75th and the 25th percentile.
<u />
25th percentile:
- X when Z has a p-value of 0.25, so X when Z = -0.675.




75th percentile:
- X when Z has a p-value of 0.75, so X when Z = 0.675.




The IQR is:

What is the diameter, in inches, of the smallest tree that is an outlier?
- The diameter is <u>1.5IQR above the 75th percentile</u>, thus:

The diameter of the smallest tree that is an outlier is of 16.36 inches.
<u />
A similar problem is given at brainly.com/question/15683591