Answer: P(x > - 0.23) = 0.41
Step-by-step explanation:
Since we are assuming that the readings at freezing on a batch of thermometers are normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = the readings at freezing on a batch of thermometers.
µ = mean temperature reading
σ = standard deviation
From the information given,
µ = 0°C
σ = 1.00°C
the probability of obtaining a reading less than -0.23°C is expressed as
P(x > - 0.23)
For x = - 0.23
z = (- 0.23 - 0)/1 = - 0.23
Looking at the normal distribution table, the probability corresponding to the z score is 0.41
