Answer:
045°
Step-by-step explanation:

Answer:
Given that,
The number of grams A of a certain radioactive substance present at time, in years
from the present, t is given by the formula

a) To find the initial amount of this substance
At t=0, we get


We know that e^0=1 ( anything to the power zero is 1)
we get,

The initial amount of the substance is 45 grams
b)To find thehalf-life of this substance
To find t when the substance becames half the amount.
A=45/2
Substitute this we get,


Taking natural logarithm on both sides we get,







Half-life of this substance is 154.02
c) To find the amount of substance will be present around in 2500 years
Put t=2500
we get,




The amount of substance will be present around in 2500 years is 0.000585 grams
Answer:
21 hours
Step-by-step explanation:
You and your friend swam for 10 hours then took a break then swam for 11 so 10+11=21 so you and your friend swam for 21 hours all together.
Answer:
x = -5
Step-by-step explanation:
Simplifying
6x + -3(x + -8) = 9
Reorder the terms:
6x + -3(-8 + x) = 9
6x + (-8 * -3 + x * -3) = 9
6x + (24 + -3x) = 9
Reorder the terms:
24 + 6x + -3x = 9
Combine like terms: 6x + -3x = 3x
24 + 3x = 9
Solving
24 + 3x = 9
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-24' to each side of the equation.
24 + -24 + 3x = 9 + -24
Combine like terms: 24 + -24 = 0
0 + 3x = 9 + -24
3x = 9 + -24
Combine like terms: 9 + -24 = -15
3x = -15
Divide each side by '3'.
x = -5
Hope this Helps
I hope this is correct
Answer:
A. 2 terms; variable = x; constant = 4.5 -------> 4.5 - 2x
B. 2 terms; variables = x and y -----------> 4.5y - 2x
C. 3 terms; variables = x and y; constant = 2 --------------> 4.5x + 2 - 3y
D. 3 terms; variables = x and y; constant = 3 --------------> x - 2y + 3
Its 100% correct just not in the order you put it in, I think you might of switched them but I just did the Warm-Up and its right my dudes :)