Question

SOMEONE PLEASE HELP ME ASAP PLEASE!!!!​

Answer 1

Answer:

Therefore,

$a_{21}=2$

Step-by-step explanation:

Given:

$A=\left[\begin{array}{ccc}3&6&9\\2&4&8\\\end{array}\right]$

To Find:

a₂₁ = ?

Solution:

Let,

$A=\left[\begin{array}{ccc}a_{11}&a_{12}&a_{13}\\a_{21}&a_{22}&a_{23}\\\end{array}\right]$

We require  ' a₂₁ ' i.e Second Row First Column Element

So on Comparing we get

∴ $a_{21}=2$

Therefore,

$a_{21}=2$