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hodyreva [135]
3 years ago
15

Pre cal help please

Mathematics
1 answer:
ss7ja [257]3 years ago
7 0

We have the following function

f(x)=\frac{3}{x+2}-\sqrt{x-3}

We want to know what is the value of f(x) when x is 19

f(19)=\frac{3}{19+2}-\sqrt{19-3}=1/7-4=\boxed{-27/7}

If you have additional questions feel free to ask.

Hope this helps.

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Answer:

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Step-by-step explanation:

9x² - 4y^{6}

can be factored as a difference of squares , that is

(U + V)(U - V)

9x² - 4y^{6} = (3x)² - (2y³)²

with U = 2x and V = 2y³

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You are studying the relationship between the history of early childhood trauma (categorized as trauma/no trauma) and weight in
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Answer:

You can decide to <u>reject</u> the Null Hypothesis at p < 0.05.

Step-by-step explanation:

In this case, the relationship between the history of early childhood trauma and weight in adulthood are being studied.

The categories of childhood trauma are:

Trauma and No trauma.

So, number of rows is, <em>r</em> = 2.

The categories of weight in adulthood are:

Low to normal, Overweight, and Obese

So, number of columns is, <em>c</em> = 3.

The distribution of the statistic \chi^{2} is chi-square with (<em>r </em>- 1)(<em>c </em>- 1) degrees of freedom, where <em>r</em> represents the number of rows in the two-way table and <em>c</em> represents the number of columns.

Compute the degrees of freedom as follows:

df = (r-1)(c-1)=(2-1) \times (3-1) = 2

It is provided that the calculated value of Chi-square test statistic is 18.26.

Compute the <em>p</em>-value of the test as follows:

p-value=P(\chi^{2}_{2}\geq 18.26)\\=0.000108\\\approx0.00011

Decision rule:

The null hypothesis will be rejected if the <em>p</em>-value of the test is less than the significance level.

The significance level is, <em>α</em> = 0.05.

<em>p</em>-value = 0.00011 < <em>α</em> = 0.05.

The null hypothesis will be rejected at 5% level of significance.

Thus, the complete statement is:

"You can decide to <u>reject</u> the Null Hypothesis at p < 0.05."

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