3b) 4 tickets/$16 = 0.25 tickets/$1
4a & 4b) You didn’t provide a photo of the problems that I need to solve them
4c) ($4/1 ticket) x (1000 tickets) = $4000
The ball will be at height 19 feet first at 0.7 sec and then at 1.42 sec.
<u>Explanation:</u>
We need to find the time at which the ball will be at height 19 feet.
Equation:
h = 3 + 34t - 16t²
19 = 3 + 34t - 16t²
16 = -16t² + 34t
-16t² + 34t - 16 = 0
On solving the equation, we get
t1 = 0.7 s and t2 = 1.42s
Therefore, the ball will be at height 19 feet first at 0.7 sec and then at 1.42 sec.
Answer:
2
Step-by-step explanation:
Simplify. Remember to follow PEMDAS and the left-> right rule.
In this case, multiply the whole number (6/1) with the numerator (1)
6 x 1 = 6
Next, simplify by dividing 6 with 3:
6/3 = 2
2 is your answer.
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X=B^1 + b^7 . i found my answer by you need to find the slope of the numbers between the table.
