<span>Let y= original side
So
A = LW
60 = (y+15)(y-13)
(y+15)(y-13) = 60
y^2 + 2y - 195 = 60
y^2 + 2y- 195 - 60 = 0
y = -17 or y= 15
Toss out the negative solution to get y= 15 as the only solution.
So the square has a side length of 15 meters.
The area of this square is 15^2 = 15*15 = 225 square meters.</span>
1 = 100%
1 % = 1/100 = 0.01
0.6 % = 0.6 · 0.01 = 0.006
Answer: C ) 0.006
Answer:
no
Step-by-step explanation:
Answer:
Option 1: 0.32
Step-by-step explanation:
Let
P(A) be the experimental probability of getting two
And
P(B) be the experimental probability of getting three
The dice is rolled 360 times.
So the sample space is n(S) = 360
P(A) = n(A)/n(S)
= 54/360
= 0.15
And
P(B) = n(B)/n(S)
= 62/360
= 0.172
As both the events A and B are mutually exclusive,
P(A or B) = P(A) + P(B)
= 0.15 + 0.172
=0.322
Rounding of to one decimal gives us:
0.32
So the probability of rolling a two or three is 0.32 ..
Answer:
b
Step-by-step explanation:
