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jok3333 [9.3K]
3 years ago
6

Multiplu (3/5) to the 3rd power

Mathematics
1 answer:
Colt1911 [192]3 years ago
5 0

Answer:

27/125

Step-by-step explanation:

3/5 × 3/5 × 3/5

3×3×3 =27

5×5×5= 125

=27/125

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You decide to use the easy hand estimates to tell your friend how far this object is from the moon Fully outstretched, your list
Studentka2010 [4]

Answer: -600 arcminutes

Step-by-step explanation:

We know that 1 degree = 60 arc minutes

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Then , by applying the famous UNITARY METHOD , we multiply 60 to the above measure so that it converts into arc minutes.

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6 0
3 years ago
the volume in a tank varies periodically. At t=0 is at its maximum of 520 gallomns and at t=6 it is at its miximum of 170 gallon
OleMash [197]

Answer:

A = 175, B = π/6, C = 345

Step-by-step explanation:

The given variation of the volume in the tank and time includes are;

At t = 0 the volume in the tank, y = Maximum volume, y_{max} = 520 gallons

At t = 6 the volume in the tank, y = Minimum volume, y_{min} = 170 gallons

The function that models the situation is y = A·cos(B·x) + C

Given that the function that models the situation is the cosine function, we have;

A = The amplitude = (The maximum - The minimum)/2

∴ A = (520 - 170)/2 = 175

A = 175

The period = The time to change from maximum to minimum = 2 × The time to change from maximum (t = 0) to minimum (t = 6)

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C = The vertical shift = Th minimum + A = (The maximum + The minimum)/2

∴ C = (520 + 170)/2 = 345

C = 345

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3 years ago
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