Is 1/2 bigger than 2/7

Mathematics

2 answers:

zaharov [31]2 years ago

8 0

Use the cross multiplication method. 1/2 is bigger.

Mazyrski [523]2 years ago

8 0

Yes because 1/2 is right on the half and 2/7 is les than the half. You can also use the butterfly method. 1 times 7 is 7 and 2 times 2 is 4 1/2 is greater because 7 us greater than 4

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Solutions of 3x+2y=4 and 6x+4y=8

Alecsey [184]

Answer:

Infinite solutions

Step-by-step explanation:

1) First, you can solve this easily by elimination. Multiply the first equation by -2 in order to cancel out terms when adding to the second equation.

2) Then, add the new set of equations together. However, everything cancels out, bringing us to 0 = 0. This means that the lines the equations make must be the same. Thus, all real numbers must make this equation true, meaning that there are infinite solutions.

4 0

2 years ago

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PLEASE HELP QUICK!!! A bowl has 85 pieces of candy. Nineteen children empty the bowl of candy. Some children take 3 pieces, some

Mekhanik [1.2K]

Answer: 3 kids take 3 pieces of candy each

Step-by-step explanation:

Let the number of children that took 3 pieces is x ( total take 3*x pieces of candy)

Number of children that took 5 pieces is y ( total take 5*y pieces of candy)

1 child took 1 piece that actually means that x+y=18 and 3*x+5*y=84.

( Because total number of all kids is 19. We just deduct one kid (Let his name is John) who took only 1 candy. So we have 19-1 =18 kids without John. The similar is with the candies. Total number is 85. We deduct 1 piece which John has taken. )

So we have 2 equations or the system of 2 equations:

1). x+y=18

2). 3*x +5*y=84

Multuply both sides of equation 1) by 3

We have 3*x+3*y=18*3

Deduct 3*y from both sides of this equation

3*x+3*y-3*y=54-3*y

3*x=54-3*y

Substitute 3*x in equation 2). by 54-3*y

2) 54-3*y+5*y=84

2*y=30

y=15 ( kids take 5 pieces of candy each)

Using equation 1) find x

x+15=18

x=3 (kids take 3 pieces of candy each)

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2 years ago

How to combine like terms

aev [14]

Example: $1x+2y+3z+4a+5x+6y+7z+8+9$

We can see that there is more than one number with the variable x, therefore, we say they're ''like terms'' and because of that they can be summed. We do this with all of the other numbers with similar variables. If no numbers with similar variables are left, like 4a, you don't do anything but write them as they are. You can also see that 8 and 9 can also be summed because neither of them has a variable, therefore they're similar.

In this step, you just do the operation with the numbers and keep the same variable.

$(1x+5x)+(2y+6y)+(3z+7z)+4a+(8+9)$