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atroni [7]
4 years ago
7

Question 4 of 10

Biology
2 answers:
alukav5142 [94]4 years ago
6 0
It would be Education
dimulka [17.4K]4 years ago
3 0

Answer:

education

Explanation:

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krek1111 [17]

Answer:

Please put this question in English and I would then love to help you. Thanks.

3 0
3 years ago
Which organisms are most critical in the nitrogen cycle?
Strike441 [17]
These are the things that convert nitrogen in the soil -cyanobacteria<span>participate. After nitrogen has been fixed, other </span>bacteria<span> convert it into </span>nitrate<span>, in a process known as nitrification.</span>
8 0
3 years ago
You select seeds from the largest, tastiest watermelons from your garden every year and use them to grow the next year's fruit.
Step2247 [10]

There would be less variability in the genes of the watermelon plants and is denoted as option A.

<h3>What is Variability?</h3>

This is defined as the difference between organisms which is caused by genetic or environmental factors.

Using the seeds from the largest, tastiest watermelons will reduce variability over time because these characteristics will become dominant.

Read more about Genetic variation here brainly.com/question/14926046

#SPJ1

5 0
2 years ago
A population of 150 individuals has an allele frequency of 0.2 for the dominant allele (H) and a frequency of 0.8 for the recess
Amanda [17]
Hardy-Weinberg Equation (HW) states that following certain biological tenets or requirements, the total frequency of all homozygous dominant alleles (p) and the total frequency of all homozygous recessive alleles (q) for a gene, account for the total # of alleles for that gene in that HW population, which is 100% or 1.00 as a decimel. So in short: p + q = 1, and additionally (p+q)^2 = 1^2, or 1
So (p+q)(p+q) algebraically works out to p^2 + 2pq + q^2 = 1, where p^2 = genotype frequency of homozygous dominant individuals, 2pq = genotype frequency of heterozygous individuals, and q^2 = genotype frequency of homozygous recessive individuals.
The problem states that Ptotal = 150 individuals, H frequency (p) = 0.2, and h frequency (q) = 0.8.
So homozygous dominant individuals (HH) = p^2 = (0.2)^2 = 0.04 or 4% of 150 --> 6 people
Heterozygous individuals (Hh) = 2pq = 2(0.2)(0.8) = 0.32 or 32% of 150
--> 48 people
And homozygous recessive individuals (hh) = q^2 = (0.8)^2 = 0.64 = 64% of 150 --> 96 people
Hope that helps you to understand how to solve these types of population genetics problems!
6 0
3 years ago
Carla wants to become a florist. Studying which of the following branches of science would be most helpful for Carla's future ca
Roman55 [17]

Answer:

there are no branches to pick from dawg

Explanation:

4 0
3 years ago
Read 2 more answers
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