Hardy-Weinberg Equation (HW) states that following certain biological tenets or requirements, the total frequency of all homozygous dominant alleles (p) and the total frequency of all homozygous recessive alleles (q) for a gene, account for the total # of alleles for that gene in that HW population, which is 100% or 1.00 as a decimel. So in short: p + q = 1, and additionally (p+q)^2 = 1^2, or 1 So (p+q)(p+q) algebraically works out to p^2 + 2pq + q^2 = 1, where p^2 = genotype frequency of homozygous dominant individuals, 2pq = genotype frequency of heterozygous individuals, and q^2 = genotype frequency of homozygous recessive individuals. The problem states that Ptotal = 150 individuals, H frequency (p) = 0.2, and h frequency (q) = 0.8. So homozygous dominant individuals (HH) = p^2 = (0.2)^2 = 0.04 or 4% of 150 --> 6 people Heterozygous individuals (Hh) = 2pq = 2(0.2)(0.8) = 0.32 or 32% of 150 --> 48 people And homozygous recessive individuals (hh) = q^2 = (0.8)^2 = 0.64 = 64% of 150 --> 96 people Hope that helps you to understand how to solve these types of population genetics problems!
Los volcanes Villarrica, Llaima, Volcán Osorno, Chillán (en Chile), Nevado de Colima, Volcán Ceboruco, Popocatépetl (en México)ejemplos de estratovolcanes
<span>B) He noticed four-fifths of the air had been used up. If by air this question is referring to oxygen, the fact that it has been used up means it has reacted, mean a substance has combusted.</span>
