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3 years ago

9

Graph the equation by plotting three

2 answers:

liraira [26]3 years ago

7 0

Answer:

-1,3

-3,-2

-5,-7

Step-by-step explanation:

7nadin3 [17]3 years ago

4 0

Answer:

(0,7.5) (1,10) (2,12.5)

Step-by-step explanation:

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In a box there are two prizes that are worth $4, a single prize worth $20, and a single prize worth $200. A player will reach in

Ronch [10]

Answer:

57

Step-by-step explanation:

The player has a 1/4 chance of drawing any of the 4 prizes. This means that the probability of drawing a prize of $4 is 1/2 because there are 2 prizes worth of $4. The probability of drawing a prize of $20 is 1/4 and the probability of drawing a prize of $200 is also 1/4. To find the fair price of the game, we have to calculate the expected value that the player will gain. This can be obtained by multiplying any possible value of a price for the probability of drawing a prize of that value and adding all the obtained values togueter. Thus, the fair price of the game is

$4 * \frac{1}{2} + 20 * \frac{1}{4} + 200 * \frac{1}{4} = 57$

6 0

3 years ago

Help me pleaseeeeeeeeee

leonid [27]

A is the answer i think

if not then c

5 0

3 years ago

Solve the following differential equation: (1− 5 y +x) dy/dx +y= 5/x −1 .<br><br> C=

Ganezh [65]

Answer:

$y(1+x)+x-5\ln xy=C$

Step-by-step explanation:

Consider the given differential equation is

$(1-\frac{5}{y}+x)\frac{dy}{dx}+y=\frac{5}{x}-1$

$(1-\frac{5}{y}+x)\frac{dy}{dx}=\frac{5}{x}-1-y$

$(1-\frac{5}{y}+x)dy=(\frac{5}{x}-1-y)dx$

Taking all variables on right sides.

$(1-\frac{5}{y}+x)dy-(\frac{5}{x}-1-y)dx=0$

$(-\frac{5}{x}+1+y)dx+(1-\frac{5}{y}+x)dy=0$

Let as assume,

$M=-\frac{5}{x}+1+y$ and $N=1-\frac{5}{y}+x$

Find partial derivatives $\frac{\partial M}{\partial y}$ and $\frac{\partial N}{\partial x}$

$\frac{\partial M}{\partial y}=1$ and $\frac{\partial N}{\partial x}=1$

Since $\frac{\partial M}{\partial y}=\frac{\partial N}{\partial x}$ , therefore the given differential equation is exact.

The solution of the exact differential equation is

$\int Mdx+\int N(\text{without x)}dy=C$

$\int (-\frac{5}{x}+1+y)dx+\int (1-\frac{5}{y})dy=C$

$yx-5\ln x+x+y-5\ln y=C$

$y+x+xy-5\ln x-5\ln y=C$

$y(1+x)+x-5(\ln x+\ln y)=C$

$y(1+x)+x-5\ln xy=C$

7 0

3 years ago

Classify the polynomial 5x^3+4x-2 by degree

Kaylis [27]

Hightest exponent is 3
cubic

C is answer

7 0

2 years ago

Read 2 more answers

Write an algebraic expression for the given quantity. Let X represent the unknown value one fourth of the sum of a number and ei

Leviafan [203]

I think that (1/4)x+8 would be your algebraic expression.

4 0

3 years ago