<span>2x - 3y - 3z = 8
We've been given the normal vector to the plane <2, -3, -3> and a point within the plane (1, -5, 3). In general if you've been given both the normal vector <a,b,c> and a point (e,f,g) within the plane, the expression for the plane will be:
ax + by + cz = d
and you can compute d by:
d = ae + bf + cg
So let's calculate d:
d = ae + bf + cg
d = 2*1 + -3*-5 + -3*3
d = 2 + 15 + -9
d = 8
And the equation for the plane is
2x - 3y - 3z = 8</span>
the fraction in the image is 2 1/2
let's try each choice
1) 2/3 x 5/2 = 10/6 = 5/3
2) 5/4 x 5/2 = 25/8
3) 3/3 x 2 1/2 = 2 1/2
4) 4/5 x 5/2 = 20/10 = 2
who is giving you these questions?
Here hope this help the solution is X= -2 and y=9
Answer:
y=-4x+9
Step-by-step explanation:
y-y1=m(x-x1)
y-(-3)=-4(x-3)
y+3=-4(x-3)
y=-4x+12-3
y=-4x+9
