I'm stuck on graphing this quadratic equation:
%2B%204x%20%2B%203" id="TexFormula1" title="y \leqslant {x}^{2} + 4x + 3" alt="y \leqslant {x}^{2} + 4x + 3" align="absmiddle" class="latex-formula">
1 answer:
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Answer:
Hope this helps
Step-by-step explanation:
Step-by-step explanation:
Hey, there!!
Let's simply work with it,
60° + 2x° + (2x+12)° = 180° { being a linear pair}.
or, 72° + 4x = 180°
4x = 180° - 70°
Therefore, the value of x is 27°.
Now,
2x° = (2×27)°= 54°
(2x+12)° = 2×27°+12°= 66°.
(x+2)= 27+ 2= 29°
Now, The left angle is 27°.
Therefore, The answer is option A.
<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>