The gcf is 5, factored it’d look like
5(w+13)
|sin(x)−sin(y)|=|2sin(x−y2)cos(x+y2)|≤|2sin(x−y2)|
Answer:
f(-3) = -2
f(-2.6) = -2
f(0.6) = 2.4
f(4.5) = 8.5
Step-by-step explanation:
(Whole question:
Evaluate the piecewise function for the given values.
Find f(-3), f(-2,6), f(0.6), and f(4.5) for f(x)={ -2 If x ≤ 0 4x. If 0 <x <1. x + 4. If x ≥ 1)
As the piecewise function shows, the function f(x) has the value of -2 for values of x lesser or equal than 0, has the value of 4x if the value of x is between 0 and 1, and has the value of x+4 for values of x greater or equal than 1.
So, for f(-3), the value of x is lesser than 0, so we have that f(-3) = -2
For f(-2.6), the value of x is lesser than 0, so we have that f(-3) = -2
For f(0.6), the value of x is between 0 and 1, so we have that f(0.6) = 4*0.6 = 2.4
For f(4.5), the value of x is greater than 1, so we have that f(4.5) = 4.5 + 4 = 8.5
First we'll do two basic steps. Step 1 is to subtract 18 from both sides. After that, divide both sides by 2 to get x^2 all by itself. Let's do those two steps now
2x^2+18 = 10
2x^2+18-18 = 10-18 <<--- step 1
2x^2 = -8
(2x^2)/2 = -8/2 <<--- step 2
x^2 = -4
At this point, it should be fairly clear there are no solutions. How can we tell? By remembering that x^2 is never negative as long as x is real.
Using the rule that negative times negative is a positive value, it is impossible to square a real numbered value and get a negative result.
For example
2^2 = 2*2 = 4
8^2 = 8*8 = 64
(-10)^2 = (-10)*(-10) = 100
(-14)^2 = (-14)*(-14) = 196
No matter what value we pick, the result is positive. The only exception is that 0^2 = 0 is neither positive nor negative.
So x^2 = -4 has no real solutions. Taking the square root of both sides leads to
x^2 = -4
sqrt(x^2) = sqrt(-4)
|x| = sqrt(4)*sqrt(-1)
|x| = 2*i
x = 2i or x = -2i
which are complex non-real values
