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love history [14]
3 years ago
12

Question 3. Simplify the following in four steps.

Mathematics
2 answers:
miss Akunina [59]3 years ago
3 0

Answer:

X ¹/₅

Step-by-step explanation:

X ⁷/₁₀

X ¹/₂

apply the exponent rule:

= X ⁷/₁₀ - ¹/₂

= X ¹/₅

podryga [215]3 years ago
3 0

Answer:

\frac{x {}^{7} }{10}  \div x {}^{ \frac{1}{2} }

=  \frac{x {}^{7} }{10}  \times \frac{1}{x {}^{ \frac{1}{2} } }

=  \frac{x {}^{ \frac{13}{2} } }{10}

=  \frac{ \sqrt{x {}^{13} } }{10}

=  \frac{x {}^{6} \sqrt{x}  }{10}

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of the 30 girls who tried out lacrosse team at Euclid Middle school, 12 were selected. Of the boys who tried out, 16 were select
Debora [2.8K]
Ratio of the number of students on the team to the number of students trying out for girls is given by
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Ratio of the number of students on the team to the number of students trying out for boys is given by
\frac{16}{40} = \frac{2}{5}

Since both ratios, simplify to \frac{2}{5}, thus <span>the ratios of the number of students on the team to the number of students trying out is the same for both boys and girls</span>.
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3 years ago
Simplify.(3x^8z^2)^4
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3 years ago
Which quantity is proportional to 40⁄8?
Nina [5.8K]
5

40/8 is 5. You can check this by multiplying 8 and 5 and seeing if it equals 40. Also, if you look at 40/8 as a fraction you can simplify it. 40/8=20/4=10/2=5/1=5

5 0
3 years ago
Explain the 2 different answers you can get when solving an equation and the variable is eliminated.
SashulF [63]

Answer:

Step-by-step explanation:

Don't know ur answer make q clear

4 0
3 years ago
Read 2 more answers
This is a Differential Equations problem, I only need help on part 1 from question five. I need steps as well, thank you.
jolli1 [7]

Answer:

a) y(t) =  \sqrt{2t + 1 }

b) 1.5 hours after thickness will be 2 inches.

Step-by-step explanation:

\frac{dy}{dt}  =  \frac{1}{y}   \\   \\ ydy = dt  \\ \\ integrating \: both \: sides \\   \\  \int y \: dy =  \int 1 \: dt \\  \\  \frac{ {y}^{2} }{2}  = t + c \\  \\  {y}^{2}  = 2t + 2c \\  \\ y (t)=  \sqrt{2t + 2c} ...(1) \\  \\ a)  \:  \: \: plug \: t = 0 \: in \: (1) \\  \\  y (0)=  \sqrt{2(0) +2 c} \\  \\ y (0)=  \sqrt{0 +2 c} \\  \\ 1 =  \sqrt{2c}  \:  \: ( \because \: y (0)=1) \\  \\  2c = 1   \:  \implies \: c =  \frac{1}{2} \\  \\ plug \: c = \frac{1}{2} \: in \: (1) \\  \\ y(t) =  \sqrt{2t + 2 \times  \frac{1}{2} } \\  \\  \huge \:  \red {y(t) =  \sqrt{2t + 1 } } \\  \\b) \:  \:  plug \: y(t) = 2 \: in \: above \: equation \\  \\ 2 =  \sqrt{2t + 1}  \\  \\ 4 = 2t + 1 \: \\  (squaring \: both \: sides) \\  \\ 4 - 1 = 2t \\  \\ 2t = 3 \\  \\ t =  \frac{3}{2}  \\  \\ t = 1.5 \: hours \\

6 0
2 years ago
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