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3 years ago

If y varies directly with x, find the constant of variation with x = 4 and y = -24

2 answers:

6 0

Use the formula y=kx for this equation.
so considering that Y equals -24 then X and K must also equal that number
we already know that X is -4 but we dont know what K is.
so we divide -24 by -4 and get an answer of a positive 6 but the answer is not proven yet.
-4 times 6 is -24 meaning that the answer is 6

Ivahew [28]3 years ago

6 0

Answer:

The constant of variation is -6.

A is correct.

Step-by-step explanation:

If y varies directly with x

$y\propto x$

y is directly proportional to x.

Equation: y=kx

where, k is constant of proportionality or constant of variation.

At x=4 , y=-24

Substitute x and y into equation and solve for k

$-24=4k$

$k=-6$

Hence, The constant of variation is -6.

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What are 26 divide by 4,340

mart [117]

$\frac { 26 }{ 4,340 } \\ \\ =\frac { 26 }{ 4\cdot { 10 }^{ 3 }+3\cdot { 10 }^{ 2 }+4\cdot { 10 }^{ 1 } } \\ \\ =\frac { 26 }{ 10\left( 4\cdot { 10 }^{ 2 }+3\cdot { 10 }^{ 1 }+4 \right) } \\ \\ =\frac { 2\cdot 13 }{ 2\cdot 5\left( 4\cdot { 10 }^{ 2 }+3\cdot { 10 }^{ 1 }+4 \right) } \\ \\ =\frac { 13 }{ 5\left( 4\cdot { 10 }^{ 2 }+3\cdot { 10 }^{ 1 }+4 \right) }$

$\\ \\ =\frac { 13 }{ 5\left( 400+30+4 \right) } \\ \\ =\frac { 13 }{ 2,000+150+20 } \\ \\ =\frac { 13 }{ 2,170 }$

------

13/2170 = 0.006 (to 3 decimal places)

4 0

3 years ago

Read 2 more answers

From a group of 12 students, we want to select a random sample of 4 students to serve on a university committee. How many combin

borishaifa [10]

Answer:

495 combinations of 4 students can be selected.

Step-by-step explanation:

The order of the students in the sample is not important. So we use the combinations formula to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

How many combination of random samples of 4 students can be selected?

4 from a set of 12. So

$C_{n,x} = \frac{12!}{4!(8)!} = 495$

495 combinations of 4 students can be selected.

8 0

3 years ago

Can sum1 help me w this plz

mel-nik [20]

Answer: x = 1.28 or -1.28

5 0

2 years ago

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What the hypothenuse of a right with length of 6 and 8

Aloiza [94]

This is a pythagorean triple --> 3-4-5
Although you notice it is doubled but with the same pattern --> 6-8-10

Thus, the hypotenuse is 10.

8 0

3 years ago

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Cate and elena were playing cards

Delicious77 [7]

There were...
11cards left.
heres why.
they started with 24 cards....
so...
24+8=32
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20-9=11

Hope i helped!!! :)
Mark me as brainliest if i helped XD

6 0

2 years ago