First factor the numerator
b^2-6b+8/b-4 * b+8/b-2
u will get
(b-2)(b-4)/(b-4)*(b-2)*b+8
those will cancel out each other will left only
b+8<span />
Answer:
(2)y²
Step-by-step explanation:
2 x y²
5. A. (4, -2)
6. C. (x, y) — (x, -y + 5)
Step-by-step explanation:
5. For the formula y = x, the x and y coordinates get swapped.
M = (-2, 4) — M’ = (4, -2)
6. If the coordinates get reflected across the x-axis, the y coordinates become negative.
(x, y) — (x, -y)
Now that the coordinates are reflected, you go 5 units up (+ 5) to get to the reflection of the coordinates if it was 5 units down before it reflected across the x-axis (- 5).
Ex. 1, 6 gets reflected across the x-axis and moved 5 units up. It’s reflection would be equivalent to (1, -1) because it moved 5 units down (1, 1) then reflected across the x-axis (1, -1).
(x, y - 5) reflected across the x-axis is equivalent to (x, -y + 5)
Answer: 46 years
Step-by-step explanation:
Let the father's age be x and the son's age be y, then 3 years ago:
Father = x - 3
son = y - 3
Then , from the first statement :
x - 3 = 3 ( y - 3 )
x - 3 = 3y - 9
x = 3y - 9 + 3
x = 3y - 6 .......................................... equation 1
In five years time
father = x + 5
son = y + 5
Then , from the second statement
x + 5 = 2 ( y + 5 )
x + 5 = 2y + 10
x = 2y + 10 - 5
x = 2y + 5 ........................ equation 2
Equating equation 1 and 2 , we have
3y -6 = 2y + 5
add 6 to both sides
3y = 2y + 5 + 6
subtract 2y from both sides
3y - 2y = 11
y = 11
substitute y = 11 into equation 1 to find the value of x
x = 3y - 6
x = 3(11) - 6
x = 33 - 6
x = 27
This means that the father is presently 27 years and the son is presently 11 years.
In four years time
father = 27 + 4 = 31
son = 11 + 4 = 15
sum of their ages in four years time will be
31 + 15 = 46 years
Answer:
12
Step-by-step explanation:
64+52=118 studied in the cafeteria or lounge
but 20 studied in both, so 118-20 = 98 studied there in total
110 -98 = 12
