3 years ago

K^{2} -9 \k^{2} -7k+12

1 answer:

azamat3 years ago

8 0

$\frac{k^2-9}{k^2-7k+12}$ Factor
= $\frac{(k+3)(k-3)}{(k-3)(k-4) }$ Eliminate (k-3)
= $}\frac{(k-3)}{(k-4) }$ Isolate k

k-3=0
k=3

k-4=0
k=4

k is equal to 3,4

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