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Gala2k [10]
3 years ago
9

A building casts a shadow 168 meters long. At the same time, a pole 5 meters high casts a shadow 20 meters long . What is the he

ight of the building ?
Mathematics
1 answer:
yawa3891 [41]3 years ago
3 0

Answer:

42

Step-by-step explanation:

The height of the pole is 4 times shorter than the length of the shadow 20÷5=4

The height of the building must be 4 times shorter than its shadow length 168÷4=42

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Help me please, it would be great
Nastasia [14]
AB²=5²+5²+5²=25+25+25=75
AB=5√3≈8.7
Answer:AB≈8.7
4 0
3 years ago
The inverse of the function graphed below is a function.?<br> A. True<br> B. False
Zinaida [17]

Step-by-step explanation:

A,true

doesn't interfere with any function restriction

3 0
3 years ago
This is a Differential Equations problem, I only need help on part 1 from question five. I need steps as well, thank you.
jolli1 [7]

Answer:

a) y(t) =  \sqrt{2t + 1 }

b) 1.5 hours after thickness will be 2 inches.

Step-by-step explanation:

\frac{dy}{dt}  =  \frac{1}{y}   \\   \\ ydy = dt  \\ \\ integrating \: both \: sides \\   \\  \int y \: dy =  \int 1 \: dt \\  \\  \frac{ {y}^{2} }{2}  = t + c \\  \\  {y}^{2}  = 2t + 2c \\  \\ y (t)=  \sqrt{2t + 2c} ...(1) \\  \\ a)  \:  \: \: plug \: t = 0 \: in \: (1) \\  \\  y (0)=  \sqrt{2(0) +2 c} \\  \\ y (0)=  \sqrt{0 +2 c} \\  \\ 1 =  \sqrt{2c}  \:  \: ( \because \: y (0)=1) \\  \\  2c = 1   \:  \implies \: c =  \frac{1}{2} \\  \\ plug \: c = \frac{1}{2} \: in \: (1) \\  \\ y(t) =  \sqrt{2t + 2 \times  \frac{1}{2} } \\  \\  \huge \:  \red {y(t) =  \sqrt{2t + 1 } } \\  \\b) \:  \:  plug \: y(t) = 2 \: in \: above \: equation \\  \\ 2 =  \sqrt{2t + 1}  \\  \\ 4 = 2t + 1 \: \\  (squaring \: both \: sides) \\  \\ 4 - 1 = 2t \\  \\ 2t = 3 \\  \\ t =  \frac{3}{2}  \\  \\ t = 1.5 \: hours \\

6 0
2 years ago
What is the nth term of this sequence?
lions [1.4K]

Answer:

D, you simply just add 1.3 each time.

4 0
3 years ago
: 11 = 1 /3 : 6<br><br> plz help
GenaCL600 [577]
<h3>Let the number be x</h3>

x:11 =  \frac{1}{3} :6

  • Divide the numbers

\frac{x}{11}  =  \frac{ \frac{1}{3} }{6}  \\  \frac{x}{11}  =  \frac{1}{18}

  • Multiply all terms by the same value to eliminate fraction denominators

11 \times  \frac{x}{11}  = 11 \times  \frac{1}{18}

  • Cancel multiplied terms that are in the denominator

x = 11 \times  \frac{1}{18}

  • Multiply the numbers

x =  \frac{11}{18}

<h2>Solved ✔︎</h2>

3 0
3 years ago
Read 2 more answers
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