Ask question

Ask question

All categories

Keith_Richards [23]

3 years ago

9

Alex has $20 and Ellen has $12 Alex saving three dollars per day and Ellen is saving five dollars per day after how many days wi

ll Alex and Ellen have the same amount of money

1 answer:

FinnZ [79.3K]3 years ago

3 0

3x+20=5x+12
-3x -3x
20= 2x +12
-12 -12
8=2x
Divide both sides by two
4=x
It will take four days (this is how to solve algebraically)

You might be interested in

Find the median of the data set: -66, -48, -52, -42

olga2289 [7]

-66, -52, - 48, -42

If you can have 2 medians (since there is only 4 numbers), it is -52 and -48

If you can only have one,then i believe you choose -50, because it is in between -48 and -52

hope this helps

6 0

3 years ago

Find the volume of the cylinder

o-na [289]

Answer:

10 ft

Step-by-step explanation:

1x10= 10

volume is found by multiplying length width and height together.

Brainliest is greatly appreciated

Answered by: Skylar

5/21/2020

1:44 PM (Eastern Time)

8 0

2 years ago

The two-way table shows information about the subjects studied

son4ous [18]

Answer:

a) 62

b) 31/45

Step-by-step explanation:

a) The table tells you there are 42 males, and 20 more females that study biology.

42 +20 = 62 . . . are male or study biology or both

__

b) Of the total of 90 people, 62 are male or study biology (or both). The probability that any person is in that category is ...

62/90 = 31/45 = P(male or biology)

4 0

2 years ago

24. Mailboxes Plus sends packages overnight for $5 plus $0.25 per ounce

velikii [3]

Answer:

his package weighs 30 ounce

Step-by-step explanation:

8 0

3 years ago

Which of the following expressions is a factor of the polynomial x 2 +3/2x-1

Elodia [21]

Answer:

$\large \boxed{\sf \ \ \ (x+2)(x-\dfrac{1}{2}) \ \ \ }$

Step-by-step explanation:

Hello,

let's solve

$x^2+\dfrac{3}{2}x-1=0\\\\ 2x^2+3x-2=0 \ \text{multiply by 2}\\\\\\$

$\Delta=b^2-4ac=9+4*2*2=9+16=25$

There are two solutions

$x_1=\dfrac{-3-\sqrt{25}}{4}\\\\x_1=\dfrac{-3-5}{4}\\\\x_1=\dfrac{-8}{4}\\\\\boxed{x_1=-2}$

And

$x_2=\dfrac{-3+\sqrt{25}}{4}\\\\x_2=\dfrac{-3+5}{4}\\\\x_2=\dfrac{2}{4}\\\\\boxed{x_2=\dfrac{1}{2}}$

So we can write

$x^2+\dfrac{3}{2}x-1\\\\=(x-x_1)(x-x_2)\\\\=(x+2)(x-\dfrac{1}{2})$

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

5 0

3 years ago