Ah clever. So you need two formulas.
1) Volume of the marble.
4(pi)r^3/3
= 4(pi)(1.4)^3/3
<span>= 11.49 (approx)
</span>
2) Formula for density.
D = M / V
= 9 / 11.49
= 0.78
0.78 < 1
Therefore the marble will float.
0.484848 . . . . .
<span>A. Integer . . . no, it's not
B. Irrational . . . no, it's not
C. Natural. . . no, it's not
D. Rational . . . Yes ! It is !
E. Whole</span> . . . no, it's not
Using the normal distribution, it is found that she scores less than 128 in 28.1% of her games.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
In this problem, the mean and the standard deviation are given, respectively, by
.
The proportion of games in which she scores less than 128 is the <u>p-value of Z when X = 128</u>, hence:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{128 - 135}{12}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B128%20-%20135%7D%7B12%7D)
Z = -0.58
Z = -0.58 has a p-value of 0.281.
She scores less than 128 in 28.1% of her games.
More can be learned about the normal distribution at brainly.com/question/24663213
#SPJ1
Answer:
I'll explain you number one
3
Step-by-step explanation:
You first subtract the single number (1) subtract to 10 which gives you 9, then you will divide 3 from 9 which gives you 3
Sorry I couldn't help you with there other ones.