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kozerog [31]
3 years ago
7

9x-2y=11 5x-2y=15 what is the solution to the above system of equations ASAP

Mathematics
2 answers:
natali 33 [55]3 years ago
8 0

9x - 2y = 11 ... (i)

5x - 2y = 15 ... (ii)

Subtracting equation (ii) from (i) we get;

4x + 0 = -4

4x=-4 , x = -1

Replacing x = -1 in equation (i) we get;

9(-1) - 2y = 11

-9 - 2y = 11

-2y = 20

y = 20 ÷ -2 = -10

The solution to the system of equations is (-1,-10).

Mice21 [21]3 years ago
7 0
Multiply the second row by -1

9x-2y=11
-5x+2y=-15

4x=-4
X=-1

9(-1)-2y=11

-9-2y=1
Add 9 to both sides
-2y=10
Y=-5

(-1,-5)
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3 years ago
How do you find the solutions to a system of equations involving quadratic functions and other functions?
mario62 [17]
Since no example is being given, let's take for instance 2 functions, one quadratic & the second linear:

y₁=ax²+bx+c & the second y₂=mx+b

The solution of those function is the coordinates (x,y) where both meet at a point . In this case (& in all other cases) you have to state that  y₁=y₂

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3 years ago
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