The place value of 3 in 630 is tens.
1)
y = ax+b
6 = 3a + b
18 = 5a + b
b = 6 - 3a
18 = 5a + 6 - 3a
2a = 12
a = 6
b = 6 - 18
b = -12
f(x) = 6x -12
2)
y = 2
No, because y ≠ 4
x = 2
No, because it's vertical<span>
</span>
y = 4
Yes, because x ∈ <span>ℝ and y = 4
</span>
x = 4
No, because it's verical
Answer:
Fifth term = 23
Step-by-step explanation:
The position to term is 'multiply by 4 then add 3'.
The formula can be :
We need to find the 5th term.
Put n = 5 in the above formula.
So, the 5th term of the given sequence is 23.
The sum of the first eight terms of the geometric sequence whose first term is -2.5 and ratio is 2 is: -637.5
The nth term of a geometric sequence is given mathematically as;
T(n) = ar^n
- where, a = first term of the geometric sequence.
- r = common ratio of the sequence
- and n = nth term of the sequence.
Therefore, the sum of the first 8 terms of the geometric sequence is;
- <em>S(8) = a + ar + ar² + ar³ + ar⁴ + ar⁵ + ar⁶ + ar⁷.</em>
In essence;
- since common ratio, r = 2
Therefore, we have;
- S(8) = -2.5(1 + 2 + 2² + 2³ + 2⁴ + 2⁵ + 2⁶ + 2⁷)
S(8) = -637.5.
Therefore, the sum of the first eight terms of the <em>geometric sequence</em> whose first term is -2.5 and ratio is 2 is: -637.5
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