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2 years ago

Please Help Me I Don’t Understand

Mathematics

1 answer:

Lyrx [107]2 years ago

6 0

32°+81°=113°

For a complete triangle to form it needs to be 180°. So all you do is subtract 180° by the sum of 32° and 81°.

180°-113°=67°

The answer is 67°

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Slope=2/3, y-intercept=-5<br>please helphelp

Shtirlitz [24]

What do u need help w
its y=2/3x - 5

3 0

3 years ago

A major cab company in Chicago has computed its mean fare from O'Hare Airport to the Drake Hotel to be $28.75 , with a standard

bulgar [2K]

Answer:

Following are the solution to the given choices:

Step-by-step explanation:

Using chebyshev's theorem :

$\to P(|(x-\mu)|\leq k \sigma)\geq 1- \frac{1}{k^2}\\\\here \\ \to \mu=28.75\\\\ \to \sigma=4.44$

In point a)

$\to |(x-\mu)|= |20.17-28.75|=8.58 and \sigma=4.44 \\\\so, \\k= \frac{ |(x-\mu)| }{\sigma}$

$= \frac{8.58}{4.44} \\\\ =1.9 \\\\ =2$

$value= (1- \frac{1}{k^2}) \times 100 \% =75\%$

In point b)

$\to (1- \frac{1}{k^2}) \times 100 \% =84\% \\\\\to (1- \frac{1}{k^2})=0.84 \\\\\to \frac{1}{k^2} =0.16 \\\\\to \frac{1}{k}=0.4\\\\ \to k=2.5 \\\\\to |(x-\mu)| \leq k \sigma \\\\= |(x-\mu)|\leq 2.5 \times 4.44 \\\\ = |(x-\mu)|\leq 1.11 \\\\ = (28.75\pm 11.1) \\\\\to \text{fares lies between}(17.65,39.85)$

In point c)

$\to 99.7 \% \\ lie \ between=28.75 \pm z(.03)\times \sigma \\\\ =28.75\pm 2.97 \times 4.44\\\\=(28.75\pm 13.1)\\\\=(15.65,41.85)\\$

In point d)

using standard normal variate

$x=20.17\\\\ z=-2 \\\\x=37.13\\\\ z=2\\\\\to P(20.17$

8 0

3 years ago

Maggie is making a necklace using a 13-inch string and identical beads.

matrenka [14]

Answer:

Step-by-step explanation:

First find out how many beads cover 1 inch of the string which is 4 beads then multiply that number, 4, by the length of the string, 13. You should get 52.

3 0

3 years ago

In a shoe store window, Sandy sees a sign announcing 25% off all sandals in stock. She finds a pair she likes that was originall

kompoz [17]

The answer is A. She will pay 11.25

7 0

3 years ago

Read 2 more answers

At a fundraiser, students sold chocolate bars with almonds and chocolate bars with walnuts. The number of chocolate bars with al

BabaBlast [244]

Answer:

Total number chocolate bars with almonds sold were approximately 66.34 and total number chocolate bars with walnuts sold were approximately 34.67.

Step-by-step explanation:

Let number chocolate bars with almonds be x

Also let number chocolate bars with walnuts be y

Given:

Number of chocolate bars with almonds that were sold one weekend was 3 less than 2 times the number of chocolate bars with walnuts.

Framing the above sentence in equation form we get;

$x=2y -3$

Also given:

The number of chocolate bars with walnuts plus 4 times the number of chocolate bars with almonds was 300.

Framing the above sentence in equation form we get;

$4x+y=300$

Now Substituting the value of x in above equation we get;

$4x+y=300\\4(2y-3)+y=300\\8y-12+y=300\\9y=300+12\\9y=312\\\\y=\frac{312}{9} \approx 34.67$

Now we will substitute the value of y in equation $x=2y -3$ we get;

$x=2y-3 = 2\times34.67 -3 = 69.34-3\approx66.34$

Hence, Total number chocolate bars with almonds sold were approximately 66.34 and total number chocolate bars with walnuts sold were approximately 34.67.

6 0

4 years ago