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3 years ago

HELP PLEASE Solve for h. −110=13+3(4h−6)

Mathematics

2 answers:

nikklg [1K]3 years ago

7 0

Answer:

h = -35/4

Step-by-step explanation:

−110 = 13+3( 4h−6)

−110 = 13 + 12h - 18

-110 - 13 + 18 = 12h

-105 = 12 h

h = -105/12 = -35/4

Tems11 [23]3 years ago

3 0

Answer: h=-8.75, h=-35/4, h=-8 3/4

Step-by-step explanation:

Multiply parentheses by three, calculate, move terms, calculate, divide both sides by 12

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ElenaW [278]

Answer:

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(Are you meaning this as the answer is a decimal?)

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8 0

3 years ago

Read 2 more answers

Find the ends of the major axis and foci

poizon [28]

The ends of the major axis is = (0, ± 13) and that of the foci is: (0,±5).

<h3>What is the axis and foci about?</h3>

The term 'foci' is known to be the point at which there is the coming together of light or any other kinds of electromagnetic radiation, particles, etc.

It is also seen as the point from which they seems to go apart.

$\frac{x^{2} }{144} + \frac{y^{2} }{169} = 1$

$\frac{x^{2} }{12^{2} } + \frac{y^{2} }{13^{2} }$

Hence, major axis is = (0, ± 13)

e = $\sqrt{1 -\frac{12^{2} }{13^{2} } }$

= 5/13

Foci is: (0± 13 x $\frac{5}{13}$ )

Foci is: (0, ±5)

Therefore, The ends of the major axis is = (0, ± 13) and that of the foci is: (0,±5).

Learn more about foci from

brainly.com/question/26250569

#SPJ1

8 0

2 years ago