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dusya [7]
2 years ago
15

Please help! really stuck on this question!

Mathematics
1 answer:
kipiarov [429]2 years ago
6 0

Answer:

132 people bought balcony seats and 450 people bought ground seats.

Step-by-step explanation:

We want to solve the system of equations:

\left\{        \begin{array}{ll}            15b+10g=6480 \\            b+g=582        \end{array}    \right

We can solve this by using substitution. From the second equation, we can subtract <em>b</em> from both sides:

g=582-b

In the first equation, we can divide both sides by five:

3b+2g=1296

Substitute:

3b+2(582-b)=1296

Distribute:

3b+1164-2b=1296

Simplify:

b+1164=1296

Solve for <em>b: </em>

<em />b=132<em />

<em />

Using the modified equation again, substitute:

g=582-(132)

Evaluate:

g=450

Therefore, 132 people bought balcony seats and 450 people bought ground seats.

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Answer:

the answer is A and C

Step-by-step explanation:

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Solve the system using the substituiton method<br> branliest offered<br> 3x-7y=10<br> x-4y=5
fiasKO [112]
Hi there!

To solve this problem using substitution, we need to set x equal to a value and substitute it into the other equation.

Since
x - 4y = 5,
x = 5 + 4y

3x - 7y = 10
3(5 + 4y) - 7y = 10
15 + 12y - 7y = 10
15 + 5y = 10
5y = -5
y = -1

Now that we know y is -1, we can substitute it back into the equation to find x:

y = -1
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x + 4 = 5
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So, your answers are x = 1 and y = -1.

Hope this helps!
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2 years ago
7.9 - 4.012. I really don't know the answer
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3.888 :))))))))))))))))))))))))))
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3 years ago
A triangle has vertices at (1,10), (-5,2), and (7,2). What is its orthocenter. Show your work.
kondor19780726 [428]

Answer:

Question: What is the orthocenter of a triangle with the vertices (-1,2) (5,2) and (2,1)?

The coordinates of point A are (-1,2), point B are (5,2), and point C are (2,1).

The orthocent is the intersection of the three altitudes. An altitude goes from a vertex and is perpendicular to the line containing the opposite side.

In the coordinate plane the equations of the altitudes can be found and then a system of equations can be solved.

Altitude 1. From point C perpendicular to the line containing side AB.

Slope of line AB is 0 (horizontal line), a vertical line is perpendicular to a horizontal line. Thus, the equation of altitude 1 is  x=2 .

Altitude 2. From point B perpendicular to the line containing side AC.

Slope of line AC is  −13 , the slope of a line perpendicular to line AC is 3. The equation of altitude 2 is  y=3x−13  

Altitude 3. From point A perpendicular to the line containing side BC.

Slope of line BC is  13 , the slope of a line perpendicular to line BC is  −3 . The equation of altitude 3 is  y=−3x−1  

The orthocenter is the point where all three altitudes intersect.

x=2  

y=3x−13  

y=−3x−1  

Use substitution to solve the first two equations  y=3(2)−13=−7  

The orthocenter is the point  (2,−7)  

we did not need the third equation, but we can use it as a check, plug the coordinates into the third equation:

−7=−3(2)−1  

−7=−6−1  

−7=−7  it works.

3 0
2 years ago
Name the property. (6x4) x3 = 6x(4x3)​
Helga [31]

Answer:

Associative

Step-by-step explanation:

When three or more numbers are multiplied, the product is the same regardless of  the way in which the numbers are grouped.

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