Answer:
an expression designed to call something to mind without mentioning it explicitly; an indirect or passing reference.
Step-by-step explanation:
What is the interquartile range of the data set below? Growth in feet of oak trees: 68,80,73,90,120,94,76,112,101,94,72 (1) 22
sdas [7]
<span>68,80,73,90,120,94,76,112,101,94,72 --->
68, 72, 73, 76, 80, 90, 94, 94, 101, 112, 120
Median = 90
Lower Median = 73
Upper Median = 101
IQR = 101 - 73
IQR = 28</span>
Answer:
2,826
Step-by-step explanation:
A tenth is the first place value after the decimal point
In this case, 2,826.<u>0</u>0
To round a number to the tenths place, we look at the hundredths place
If the number is 5 or more, we add 1 to the tenths place, and leave the numbers to the right 0's
If the number is 4 or less, we keep the number as it is in the tenths place, and leave the numbers to the right 0's
In this case, the hundredths place is a 0, which is less than 4, so we keep the 0 in the tenths place, and leave the to the right 0's.
Thus, our final answer is 2,826.
Area = l * w
A = 10 1/2 * 12 5/8
A = 21/2 * 101/8 = 2121/16
A = 132.56 ft²
Answer:
x = 3
y = 1
Step-by-step explanation:
9x - y = 26 ---------------(I)
9x + y = 28 ---------------(II)
9x - y = 26
9x = 26 + y
Substitute 9x = 26 + y in equation (II)
26 + y + y = 28 {add like terms}
26 + 2y = 28 {subtract 26 from both sides}
2y = 28 - 26
2y = 2 {divide both sides by 2}
y = 2/2
y = 1
Substitute y =1 in equation (I)
9x - 1 = 26
9x = 26 + 1
9x = 27
x = 27/9
x = 3
x = 3
y = 1
