Consider the intergers as, x and x+1
x+(x+1)=31
2x+1=31
2x=30
x=15
So, (x+1)=(15+1)=16 would be larger number.
Answer: 2/3
Step-by-step explanation:
5/6 divided 5/4
5 times 4 and 6 times 5
equals 20/30
simplify 20/30 =2/3
3x - 2y = 13
-2y = -3x + 13
y = 3/2x - 13/2...slope is 3/2, y int is -13/2
2x + 3y = -16
3y = -2x - 16
y = -2/3x - 16/3...slope = -2/3, y int is -16/3
perpendicular lines will have negative reciprocal slopes. To find the negative reciprocal of a number, flip the number and change the sign.
On the 1st equation, the slope was 3/2....find its negative reciprocal.....flip it, making it 2/3....change the sign...making it -2/3. So the negative reciprocal of 3/2 is -2/3.
So if one equation has a slope of 3/2 and another equation has a slope of -2/3, then these lines are perpendicular <==
Suppose that X is a vertical segment that lies on the y-axis with its beginning at origin and ending at the point (0,4). Then the length of this segment is 4 units.
If you vertically compress this segment by factor of 1/4 with the centre of compression at the origin, you recieve a segment that also lies on the y-axis with its beginning at origin and ending at the point (0,1) (the length of this image segment is 1 unit).
So, the question is: if a segment that lies on the y-axis with its beginning at origin and ending at the point (0,4) is vertically compressed <span>by factor of 1/4 with the centre of compression at the origin, what is the image of this transformation?
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