-x-8y+5
Hope this helps, we have same name btw
Answer:
XY (height) is approximately 20.8 feet
Step-by-step explanation:
let h = XY
tan60° = h/12
h = 12·tan60°
h = 20.78 ft
<span>P(at least 1 ) = 1 - P(exactly none) = 1 - (4/5)^6 = .738
Hope this helps!!!:)</span>
Let the side of the garden alone (without walkway) be x.
Then the area of the garden alone is x^2.
The walkway is made up as follows:
1) four rectangles of width 2 feet and length x, and
2) four squares, each of area 2^2 square feet.
The total walkway area is thus x^2 + 4(2^2) + 4(x*2).
We want to find the dimensions of the garden. To do this, we need to find the value of x.
Let's sum up the garden dimensions and the walkway dimensions:
x^2 + 4(2^2) + 4(x*2) = 196 sq ft
x^2 + 16 + 8x = 196 sq ft
x^2 + 8x - 180 = 0
(x-10(x+18) = 0
x=10 or x=-18. We must discard x=-18, since the side length can't be negative. We are left with x = 10 feet.
The garden dimensions are (10 feet)^2, or 100 square feet.
Well, first you would have to draw the three pizzas, then spilt them all in half, so each friend would have a half of pizza! Hope this helped!
