Grouping 1 10 as 10 1's is the same because you have just rearranged the numbers but they equal the same
Step-by-step explanation:
y = -3x² + mx + 10
dy/dx = -6x + m.
When dy/dx = 0, -6x + m = 0. => x = m/6.
We have y = -3(m/6)² + m(m/6) + 10 = 37.
=> -m²/12 + m²/6 = 27
=> -m² + 2m² = 324
=> m² = 324
=> m = 18 or m = -18.
Assuming T, B and N are all on the same line, then we can say
BT + TN = BN
which is the segment addition postulate.
Subtract TN from both sides to get
BT + TN = BN
BT + TN - TN = BN - TN
BT = BN - TN
BN - TN = BT
Which is what choice C is saying. Therefore the answer is choice C.
