the probability that if you pick only one, it's defective, is 250/6700
Therefore, the probability that one is not defective is 6450/6700
a. You want all 4 to not be defective: (6450/6700)^4
b. all 100 have to be not defective: (6450/6700)^100
If you type this into a calculator, you will get about 0.022, so a probability of 2 % that all of them are not defective. As this is a very small probability, the outlet should plan with returned tires.
Answer:
the firsts third and last one
Step-by-step explanation:
hope this helped
L=2W-4
PERIMETER=2L+2W
58=2(2W-4)+2W
58=4W-8+2W
58=6W-8
6W=58+8
6W=66
W=66/6
W=11 ANS. FOR THE WIDTH.
L=2*11-4
L=22-4
L=18 ANS. FOR THE LENGTH.
PROOF:
58=2*18=2*11
58=36+22
58=58
Answer:
Step-by-step explanation:
The answer is .50
Solving for the amount of maturity given that it is compounded monthly for 1 year with an interest of 3%, we have the formula and solution below:
A = P (1+r/n)^rn
A = $5,000 (1.040417)
A =$5202.085
For compounded daily, we have the solution below:
A = $5,000 (1.040443)
A = $5202.215
The difference in amount is shown below:
Difference = $5202.215 - $5202.085
Difference = $0.13