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tresset_1 [31]
3 years ago
10

Find the value of r in (4,r),(r2) so that the slope of the line containing them is -5/3 A.-1/7 B-7. C 1/7 D. 7

Mathematics
2 answers:
inessss [21]3 years ago
4 0

Answer:

Option D (7).

Step-by-step explanation:

The formula for gradient of the straight line is given by:

m = (y2 - y1)/(x2 - x1); where (x1, y1) and (x2, y2) are two fixed points on the straight line. It is given that (x1, y1) = (4, r) and (x2, y2) = (r, 2). The gradient of the straight line is given by -5/3. To find the value of r, simply substitute all the values in the gradient equation. Therefore:

-5/3 = (2 - r)/(r - 4).

Cross Multiplying:

-5*(r - 4) = 3*(2 - r).

-5r + 20 = 6 - 3r.

-2r = -14.

r = 7.

Therefore, Option D is the correct answer!!!

bonufazy [111]3 years ago
3 0

Answer:

Option D (7).

Step-by-step explanation:

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(a)

Number of ways of Selecting 2 integers from 50 Integers ,so that their sum is even,

   =Selecting 2 Even integers from 50 Even Integers , and Selecting 2 Odd integers from 50 Odd integers ,as Order of arrangement is not Important, ,

        =_{2}^{50}\textrm{C}+_{2}^{50}\textrm{C}\\\\=\frac{50!}{(50-2)!(2!)}+\frac{50!}{(50-2)!(2!)}\\\\=\frac{50!}{48!\times 2!}+\frac{50!}{48!\times 2!}\\\\=\frac{50 \times 49}{2}+\frac{50 \times 49}{2}\\\\=1225+1225\\\\=2450

=4900 ways

(b)

Number of ways of Selecting 2 integers from 100 Integers ,so that their sum is Odd,

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        =_{1}^{50}\textrm{C}\times _{1}^{50}\textrm{C}\\\\=\frac{50!}{(50-1)!(1!)} \times \frac{50!}{(50-1)!(1!)}\\\\=\frac{50!}{49!\times 1!}\times \frac{50!}{49!\times 1!}\\\\=50\times 50\\\\=2500

=2500 ways

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