Find three consecutive odd integers such that six times the second decreased by twice the first is equal to twenty more than the
1 answer:
You might be interested in
Answer:
Function <u>#2</u> has a greater minimum.
#3 < #1 < #2
Step-by-step explanation:
In the picture attached, the question is shown.
The minimum of Function #1 is located at (3, -1). This is seen in the picture.
The minimum of Function #2 is located at (1.5, 1). We can see in the table that the function is symmetric respect 1.5 (half-point between 1 and 2).
The function y = x² + 3x - 4 has its minimum at its vertex:
x-coordinate of vertex: x = -b/(2a) = -3/(2*1) = -1.5
y-coordinate of vertex: y = (-1.5)² + 3(-1.5) - 4 = -6.25
So, the minimum of Function #3 is located at (-1.5, -6.25)
