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djyliett [7]
3 years ago
15

Find three consecutive odd integers such that six times the second decreased by twice the first is equal to twenty more than the

sum of the second and third
Mathematics
1 answer:
Kitty [74]3 years ago
6 0
Let
x--------> the first <span>odd integer
x+2-----> </span>the second odd integer
x+4-----> the third odd integer

we know that
6(x+2)-2x=20+(x+2)+(x+4)
6x+12-2x=26+2x
4x-2x=26-12
2x=14
x=7

the answer is 
the numbers are
7, 9 and 11
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A company uses two vans to transportworkers from a free parking lot to theworkplace between 7:00 and 9:00 a.m.One van has 6 more
OverLord2011 [107]
X = small van capacity, y = larger van capacity
y = x + 6

2x + y = 57
now we sub in x + 6 for y
2x + x + 6 = 57
3x + 6 = 57
3x = 57 - 6
3x = 51
x = 51/3
x = 17

y = x + 6
y = 17 + 6
y = 23

small van (x) has 17 seats and large van (y) has 23 seats

3 0
3 years ago
Whitch expression is equivalent to 7 to the 3rd power? 7*7*7. Or 21. Or. 3 to the power of. Or. 10
laila [671]

Answer:

7x7x7

Step-by-step explanation:

8 0
3 years ago
“Use the rule 5n - 2 to complete the missing entry labeled A and B in the input-output table below”
Shtirlitz [24]

Step-by-step explanation:

5n-2

5(4) - 2

20-2=18

A= 18

5n - 2 =48

5n=48+2

5n=50

divide by 5

n= 10

B=10

7 0
3 years ago
Consider the quadratic functions represented below. Function #1 Function #2 x y -1 14 -0 6 1 2 2 2 3 6 4 14 Which function has a
Harrizon [31]

Answer:

Function <u>#2</u> has a greater minimum.

#3 < #1 < #2

Step-by-step explanation:

In the picture attached, the question is shown.

The minimum of Function #1 is located at (3, -1). This is seen in the picture.

The minimum of Function #2 is located at (1.5, 1). We can see in the table that the function is symmetric respect 1.5 (half-point between 1 and 2).

The function y = x² + 3x - 4 has its minimum at its vertex:

x-coordinate of vertex: x = -b/(2a) = -3/(2*1) = -1.5

y-coordinate of vertex: y = (-1.5)² + 3(-1.5) - 4 = -6.25

So, the minimum of Function #3 is located at (-1.5, -6.25)

4 0
3 years ago
A machine with velocity ratio of 5 is used to raise a load with an effort of 500N . If the machine is 80% efficient , determine
Yanka [14]

Answer:

Solutions given:

Velocity ratio V.R =5

effort =500N

efficiency =80%

magnitude of load=?

mechanical advantage [M.A ]

we have

efficiency =M.A/V.R*100%

80=M.A./5*100

80/100*5=M.A

M.A.=4

again

we have

M.A =load/effort

4=load/500

load=500*4

load=2000N

<h3><u>the magnitude of the load is 2000N</u>.</h3>
7 0
3 years ago
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