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sergij07 [2.7K]
3 years ago
6

Problem 1 Calculating the tip when you go to a restaurant is not difficult, but your restaurant wants to suggest a tip according

to the service diners receive. Write a program that calculates a tip according to the diner’s satisfaction as follows: •Ask for bill amount •Ask for the diners’ satisfaction level using these ratings: 1 = Totally satisfied, 2 = Satisfied, 3 = Dissatisfied. •If the diner is totally satisfied, calculate a 20 percent tip. •If the diner is satisfied, calculate a 15 percent tip. •If the diner is dissatisfied, calculate a 10 percent tip. •Report the satisfaction level and tip in dollars and cents Format tips to 2 decimal points; if the bill is 105$ and satisfaction level is 3, then the tip will be $10.50
Computers and Technology
1 answer:
DIA [1.3K]3 years ago
4 0

Answer:

bill = float(input("Enter the bill amount: "))

rating = int(input("Choose a rating: 1 = Totally satisfied, 2 = Satisfied, 3 = Dissatisfied.: "))

if rating is 1:

   tip = bill * 0.2

elif rating is 2:

   tip = bill * 0.15

elif rating is 3:

   tip = bill * 0.1

print("The rating is: " + str(rating))

print("The tip is: $%.2f" % (tip))

Explanation:

*The code is in Python

- Ask the user for the <em>bill</em> and <em>rating</em>

- Depending on the <em>rating</em>, calculate the <em>tip</em> using <u>if else</u> statement i.e. If the rating is chosen as 1, calculate the tip by taking 20 percent of the bill.

- Print the <em>rating</em> and the <em>tip</em>

You might be interested in
Write a program that prompts the user to enter the center and a point on the circle. The program should then output the circle’s
sergij07 [2.7K]

Here is the code in C++.

#include <bits/stdc++.h>

using namespace std;

// function to calculate distance between two points

double distance(int a,int b,int c,int d )

{

 // return the distance between center and point

  return sqrt(pow(c - a, 2) +

               pow(d - b, 2) * 1.0);

}

// driver function

int main()

{

// variables to store coordinates

int x1,y1,x2,y2;

cout<<"Please Enter the center(x y) of the circle: ";

//reading center

cin>>x1>>y1;

cout<<"\nPlease Enter a point(x1 y1) on the circle:";

//reading point

cin>>x2>>y2;

// calling distance() function with 4 parameters

double rad=distance(x1,y1,x2,y2);

// calculating Radius and print

cout<<"Radius of circle is: "<<rad<<endl;

// calculating Diameter and print

cout<<"Diameter of circle is: "<<2*rad<<endl;

// calculating Circumference and print

cout<<"Circumference of circle is: "<<2*3.14*rad<<endl;

// calculating Area and print

cout<<"Area of circle is: "<<3.14*rad*rad<<endl;

return 0;

}

Explanation:

First it will read coordinates of center and point on the circle.The distancebetween center and point on circle is Radius. Call distance() function withfour parameters which are coordinates of center and point. This will return the value of Radius. Diameter is 2 times of Radius.Diameter of a circle is 2*3.14*Radius. and Area of the circle is calculate as 3.14*Radius*Radius. After finding these value print them.

Output:

Please Enter the center(x y) of the circle: 0 0

Please Enter a point(x1 y1) on the circle: 3 4

Radius of circle is: 5

Diameter of circle is: 10

Circumference of circle is: 31.4

Area of circle is: 78.5

4 0
3 years ago
Victoria is creating a brochure for her photography studio. She designed the layout and placed a photo in the center of the page
cestrela7 [59]

Assuming Victoria is using Adobe Photoshop to create her brochure, below are the steps she is required to follow.

She should first open the image on Photoshop, click on the image option and select duplicate just in case the resized image is not what she wants.

Still on the image option, she should select Image size. A screen will pop up at this point, indicating the image’s current size. For the purposes of image resizing, Victoria should select Pixel dimensions category.

She should be able to type her preferred dimensions for both the width and height. She should make sure ‘Constrain Proportions’ is unchecked to be able to type in separate values.

If she decides to use the photo editing program, she can simply click on the image, and if resize handles appear around it, she can click and drag those to the desired size.


3 0
3 years ago
Perform algorithm time measurement for all three quadratic sorting algorithms for Best Case (already sorted), Average Case (rand
Kaylis [27]

Answer:

Experiment size : 50,000

==================================

Selection sort :

---------------------------------------------------------

Worst case : 0.162

Average case : 0.116

Best case : 0.080

Insertion sort :

---------------------------------------------------------

Worst case : 0.162

Average case : 0.116

Best case : 0.080

Bubble sort:

--------------------------------------------------------

Worst case : 0.211

Average case : 0.154

Best case : 0.117

Experiment size : 100,000

==================================

Selection sort :

---------------------------------------------------------

Worst case : 0.316

Average case : 0.317

Best case : 0.316

Insertion sort :

---------------------------------------------------------

Worst case : 0.316

Average case : 0.317

Best case : 0.316

Bubble sort:

--------------------------------------------------------

Worst case : 0.482

Average case: 0.487

Best case : 0.480.

Experiment size : 200,000

==================================

Selection sort :

---------------------------------------------------------

Worst case : 1.254

Average case : 1.246

Best case : 1.259

Insertion sort :

---------------------------------------------------------

Worst case : 1.254

Average case : 1.246

Best case : 1.259

Bubble sort:

--------------------------------------------------------

Worst case : 1.990

Average case : 2.009.

Best case : 1.950

Explanation:

[NB: since it is very long there is the need for me to put it it a document form. Kindly check the doc. Files. The file A is the sort Analysis.Java file and the file B is the sort.Java file].

The concept of algorithm time measurement strictly depends on the following;

=> The measurement of time, space or energy on different sizes.

=> Plotting of the measurements and characterizing them.

=> Running or implementation of the algorithm.

Programming language such as Java can be used in accessing the operating system clock and Java had two static methods.

KINDLY CHECK BELOW FOR THE ATTACHMENT.

Download doc
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark"> doc </span>
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark"> doc </span>
5 0
3 years ago
What is the shortcut to select all text?
abruzzese [7]
Highlight everything with your curser.
7 0
3 years ago
Read 2 more answers
What is an 8086 microprocessor used for
Liula [17]
A sixteen bit microprocessor chip used in early IBM PCs. The Intel 8088 was a version with an eight-bit externaldata bus.

The Intel 8086 was based on the design of the Intel 8080 <span>and </span>Intel 8085 (it was source compatible with the 8080)with a similar register set, but was expanded to 16 bits. The Bus Interface Unit fed the instruction stream to theExecution Unit through a 6 byte prefetch queue, so fetch and execution were concurrent - a primitive form ofpipelining (8086 instructions varied from 1 to 4 bytes).

It featured four 16-bit general registers, which could also be accessed as eight 8-bit registers, and four 16-bit indexregisters (including the stack pointer). The data registers were often used implicitly by instructions, complicatingregister allocation for temporary values. It featured 64K 8-bit I/O (or 32K 16 bit) ports and fixed vectored interrupts.There were also four segment registers that could be set from index registers.

The segment registers allowed the CPU to access 1 meg of memory in an odd way. Rather than just supplyingmissing bytes, as most segmented processors, the 8086 actually shifted the segment registers left 4 bits and addedit to the address. As a result, segments overlapped, and it was possible to have two pointers with the same valuepoint to two different memory locations, or two pointers with different values pointing to the same location. Mostpeople consider this a brain damaged design.

Although this was largely acceptable for assembly language, where control of the segments was complete (it couldeven be useful then), in higher level languages it caused constant confusion (e.g. near/far pointers). Even worse, thismade expanding the address space to more than 1 meg difficult. A later version, the Intel 80386, expanded thedesign to 32 bits, and "fixed" the segmentation, but required extra modes (suppressing the new features) forcompatibility, and retains the awkward architecture. In fact, with the right assembler, code written for the 8008 canstill be run on the most <span>recent </span>Intel 486.

The Intel 80386 added new op codes in a kludgy fashion similar to the Zilog Z80 and Zilog Z280. The Intel 486added full pipelines, and clock doubling (like <span>the </span>Zilog Z280).

So why did IBM chose the 8086 series when most of the alternatives were so much better? Apparently IBM's own engineers wanted to use the Motorola 68000, and it was used later in the forgotten IBM Instruments 9000 Laboratory Computer, but IBM already had rights to manufacture the 8086, in exchange for giving Intel the rights to its bubble memory<span> designs.</span> Apparently IBM was using 8086s in the IBM Displaywriter word processor.

Other factors were the 8-bit Intel 8088 version, which could use existing Intel 8085-type components, and allowed the computer to be based on a modified 8085 design. 68000 components were not widely available, though it could useMotorola 6800 components to an <span>extent.
</span>
Hope this helps
7 0
3 years ago
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