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Xelga [282]
3 years ago
8

What is the difference between a fragment shader and vertex shader? How do they relate?

Computers and Technology
1 answer:
Inessa05 [86]3 years ago
5 0

Answer:

vertex  shader is performed, while on each pixel,  fragment shader is achieved. The shader fragment is implemented after the implementation of shader vertex

Explanation:

A shader fragment is the same as a shader for pixels.

A major distinction is that a shader of the vertex can alter the vertices characteristics. whixch are the end points of polygon

On the other side, the fragment shader is responsible for the display of the pixels between the vertices. They are interpolated by particular guidelines between the specified vertices.

On each vertex, vertex  shader is performed, while on each pixel,  fragment shader is achieved. The shader fragment is implemented after the implementation of shader vertex

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In most programming languages, the compiler carries a preprocessing step to determine if certain statements will compile. For in
MakcuM [25]

Answer:

See explaination for program code

Explanation:

package com.company;

import java.io.IOException;

import java.nio.file.Files;

import java.nio.file.Paths;

import java.util.Stack;

/*

* A program which reads input from given text filename and prints

* whether it passed the pre-processing stage or not

* Sample input

* int A = (a + b);static void display(int x)

* {

* //A sample input file

* }

* */

public class MyPreprocessor {

/*

* Reads input from filename and returns a string

* containing whole text

* */

public String readInput(String filename) {

String content = "";

try {

content = new String(Files.readAllBytes(Paths.get(filename)));

} catch (IOException e) {

e.printStackTrace();

}

return content;

}

/**

* Filters input since we are only concerned with

* a subset of input = '{}[]()/*'

*/

public String filterText(String text) {

String output = "";

for(int i = 0;i<text.length();++i) {

switch (text.charAt(i)) {

case '[':

case ']':

case '{':

case '}':

case '(':

case ')':

case '*':

case '/':

output += text.charAt(i);

}

}

return output;

}

/*

* Uses stack to determine if input is valid or not

* */

public boolean parse(String input) {

Stack<Character> St = new Stack<Character>();

// '$' is special symbol to represent bottom of stack

St.push('$');

for(int i = 0;i<input.length();++i) {

Character symbol = input.charAt(i);

if(St.peek().equals(getOpenSymbol(symbol)))

St.pop();

else St.push(symbol);

}

return St.peek() == '$';

}

private static Character getOpenSymbol(Character symbol) {

switch (symbol) {

case '}': return '{';

case ']': return '[';

case ')': return '(';

case '*': return '*';

case '/': return '/';

default: return ' ';

}

}

public static void main(String[] args) {

MyPreprocessor preprocessor = new MyPreprocessor();

String inputText = preprocessor.readInput("src/input.txt");

String filteredInput = preprocessor.filterText(inputText);

if(preprocessor.parse(filteredInput))

System.out.println("preprocessing passed.");

else System.out.println("preprocessing failed!");

}

}

6 0
4 years ago
Help me
denis23 [38]

Answer:

a = 6, b = 0

Explanation:

The loop ran 3 times before b == 0. "while ((b != 0)" is essentially saying: 'While b is not equal to 0, do what's in my loop'. Same general thing with "&& ((a / b) >= 0)". The "&&" is specifying that there should be another loop condition, while the rest states: 'as long as a ÷ b is greater than 0, do what's in my loop'. If both of these conditions are met, the loop will run, It will continue this until the conditions are not met. Hope that helped! :)

7 0
3 years ago
Dakota's friend Stephen created a cypher using the QWERTY keyboard, but Dakota is confused. Stephen said to move one to the righ
Radda [10]

Answer:

people are so confusing nowadays... Mr. Kopin told me to get him a coffee. I'm not his servant!

Explanation: QWERTY Q=P A=L Z=M and the others are what is to the left of them.

5 0
3 years ago
Create a structure representing a student. The member variables should include student name, student ID, and four test grades fo
Neporo4naja [7]

Answer:

Output:

Name: Brainly

ID:0001

Write the 4 tests grades of the student separated by space :10 9 8 10

Brainly

0001

10 9 8 10

Average :9.66667

'1' to continue '0' to exit :

Explanation:

#include<iostream>

#include<string>

using namespace std;

//variables declaration

struct Student {

  string id; //string declaration ID

  string name; // string declaration name

  int grades[4]; //array of 4 because it is 4 grades

};

//definition of the function get information

void inputData(Student &s){

 

   

   cout << "Name:" ;

   getline(cin,s.name);

   cout << "ID:";

   cin >> s.id;

   cout << "Write the 4 tests grades of the student separated by space :";

   for (int i = 0; i<4; i++)

       cin >> s.grades[i];

}

//definition of the function of average

double inputAvg(Student s){

   double summation;

   int temporary;

   double average;

   for (int i = 0; i<4; i++){  

      for (int j = i; j<4; j++){

         if (s.grades[j] > s.grades[i]){

             temporary = s.grades[i];

             s.grades[i] = s.grades[j];

             s.grades[j] = temporary;

         }

      }

    }

    summation = 0;

    for (int i = 0; i<3; i++){

        summation = summation + s.grades[i];  

    }

    average = summation/3;

    return average;

}

void disp(Student *s){

   cout << s->name << endl;

   cout << s->id << endl;

   for (int i = 0; i<4; i++)

       cout << s->grades[i] << " ";

   cout << endl;

   cout << "Average :" << inputAvg(*s) << endl;

   

}

int main(){

  Student st;

  int ch;

  while(true){

      inputData(st);

      disp(&st);

      cout << " '1' to continue '0' to exit :";

      cin >> ch;

      if (ch == 0)

         break;      

  }

  return 0;

}

6 0
3 years ago
You can insert pictures,such as scanned photographs, line art, and artwork, into a presentation. (points : 2) true false
Lady bird [3.3K]
True, i have done this before in my presentation slides
5 0
3 years ago
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