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3 years ago

Meg[] elements = {new Lois(), new Stewie(), new Meg(), new Brian()}; for (int i =0; i

Computers and Technology

1 answer:

Stells [14]3 years ago

7 0

Complete question is attached as snapshot.

Answer:

This will result in a compilation error.

Here's the inheritance hierarchy:

Meg -> Lois -> Brian -> Stewie

Now Meg has 2 public Fxns, a() and toString().

Lois inherits from Meg and all its public functions as well but, overrides the a() fxn of its super class.

So finally Lois has fxns a(), b() and toString().

Brian extends Lois and inherits all the above listed fxns of Lois, but overrides the b() and toString() fxns.

Stewie extends Brian and inherits all the fxns of Brian, but overrides the a() and toString() fxns.

In the Main driver fxn, we call a() and b() methods of all these classes but, the base class Meg has no b() and it is not extending any class so its not available in its scope.

This results in a compilation error.

Explanation:

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2 years ago

What is the first and last value of i to be displayed by the following code snippet? int n = 20; for (int i = 0; i <= n; i++)

frutty [35]

Answer:

The first value of i is 0 and last value of i is 20.

Explanation:

The following are the description of a given loop.

In this problem, there are two loops one is the internal loop and the other is the external loop

In the outer loop, the value of " i" is initialized with "0" So the first value is printed 0 in the console.

For one value of "i" all the inner loop is executed.

The loop is executed is less equal to 20 that's why the last value of "i" is printed 20 in the console window.

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3 years ago