Answer:
Hence, the complex fraction is equal to
[-2y + 5x]/[3x - 2y] that is,
[-2y + 5x] divided by [3x - 2y]
Step-by-step explanation:
Complete Question
Which expression is equal to the complex fraction
[-2/x + 5/y] divided by [3/y - 2/x]
We first take the LCM of each of these
[-2/x + 5/y] = [(-2y + 5x)/xy]
[3/y - 2/x] = [(3x - 2y)/xy]
[-2/x + 5/y] ÷ [3/y - 2/x] becomes
[(-2y + 5x)/xy] ÷ [(3x - 2y)/xy]
= [(-2y + 5x)/xy] × [xy/(3x - 2y)]
= [-2y + 5x]/[3x - 2y]
Hope this Helps!!
Let x = 32.323232…
Then 100x = 3232.323232…
It follows that
100x - x = 3232.323232… - 32.323232…
99x = 3200
x = 3200/99
Answer:
190
Step-by-step explanation:
f(1)=8
f(2)=3f((2-1))-2, f(2)=22
f(3)=3f((3-1))-2, f(3)=64
f(4)=3f((4-1))-2, f(4)=190
Answer:
it's 30
Step-by-step explanation:
30+4_2= dakukabilat
Alright give me a second ok
