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HACTEHA [7]
2 years ago
15

Given f(1) = 8 and f(n) = 3 f(n-1) - 2 then f (4) =

Mathematics
1 answer:
Ronch [10]2 years ago
8 0

Answer:

190

Step-by-step explanation:

f(1)=8

f(2)=3f((2-1))-2, f(2)=22

f(3)=3f((3-1))-2, f(3)=64

f(4)=3f((4-1))-2, f(4)=190

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tigry1 [53]

Answer:

1

Step-by-step explanation:

1 that is to the power of 0 is 1

5 0
2 years ago
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What is the value of -4.4+ (5-2)(-6)?
Pachacha [2.7K]

Answer:

Step-by-step explanation:

-4.4 + (5-2)(-6) = -4.4 + (3)(-6) = -4.4 + (-18) = - 22.4

8 0
2 years ago
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Solve the equation using square roots. x2 + 5 = 41
Stells [14]
X*2 +5 =41
Subtract 5 from both sides
X*2=36

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X=6

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This’s correct!
3 0
3 years ago
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Mike pays $20 per hour for algebra tutoring. The equation y = 20x relates the cost of tutoring (y) to the number of hours (x) he
kotykmax [81]

The unit rate in the equation is 20.

Option C) is the correct answer.

<u>Step-by-step explanation</u>:

Step 1 :

In the given equation y = 20x

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x ⇒ total number of hours for tutoring

20 ⇒  the cost per hour of tutoring

y ⇒ the total cost for total hours of tutoring

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8 0
3 years ago
Write a polynomial function of minimum degree in standard form with real coefficients whose zeros and their multiplicities inclu
Softa [21]

<u>Answer-</u>

<em>The polynomial function is,</em>

y=x^4-10x^3+38x^2-64x+40

<u>Solution-</u>

The zeros of the polynomial are 2 and (3+i). Root 2 has multiplicity of 2 and (3+i) has multiplicity of 1

The general form of the equation will be,

\Rightarrow y=(x-(2))^2(x-(3+i))(x-(3-i))   ( ∵ (3-i) is the conjugate of (3+i) )

\Rightarrow y=(x-2)^2(x-3-i)(x-3+i)

\Rightarrow y=(x^2-4x+4)((x-3)-i)((x-3)+i)

\Rightarrow y=(x^2-4x+4)((x-3)^2-i^2)

\Rightarrow y=(x^2-4x+4)((x^2-6x+9)+1)

\Rightarrow y=(x^2-4x+4)(x^2-6x+10)

\Rightarrow y=x^2x^2-6x^2x+10x^2-4x^2x+4\cdot \:6xx-4\cdot \:10x+4x^2-4\cdot \:6x+4\cdot \:10

\Rightarrow y=x^4-10x^3+14x^2+24x^2-40x-24x+40

\Rightarrow y=x^4-10x^3+38x^2-64x+40

Therefore, this is the required polynomial function.


4 0
3 years ago
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