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insens350 [35]
4 years ago
10

A line that includes the points (-6,-5) and (j,4) has an undefined slope. What is the value of j?

Mathematics
1 answer:
solong [7]4 years ago
7 0

if we have an undefined line, that simply means the fraction form of the slope has a 0 at the bottom, namely  


\bf slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{}{\underset{\underset{here}{\uparrow}}{0}}


therefore then


\bf (\stackrel{x_1}{-6}~,~\stackrel{y_1}{-5})\qquad (\stackrel{x_2}{j}~,~\stackrel{y_2}{4}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{4-(-5)}{j-(-6)}\implies \cfrac{4+5}{j+6}\implies \stackrel{\stackrel{und efined}{\downarrow }}{\cfrac{~~~~}{0}} \\\\\\ \stackrel{\textit{therefore thus}}{j+6=0}\implies j=-6

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Hello from MrBillDoesMath!

Answer:

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Discussion:

The question can be written as

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