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Korolek [52]
3 years ago
7

7 people are running in a race. If we only care about first, second and third place, how many possible outcomes are there?

Mathematics
1 answer:
mr_godi [17]3 years ago
8 0
7\cdot6\cdot5=210
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Which side lengths form a right triangle?
STALIN [3.7K]

Answer:

8, 15, 17  and \sqrt{2} , \sqrt{2}, 2

Step-by-step explanation:

c=\sqrt{a^2+b^2}

33=/=\sqrt{5^2+\sqrt{8}^2 }

17=\sqrt{8^2+15^2}

2=\sqrt{\sqrt{2}^2+\sqrt{2}^2  }

3 0
3 years ago
Answer the question below please
PSYCHO15rus [73]

Answer:

x=7

Step-by-step explanation:

AC=3x+3  AB=-1+2x and BC=11

AC = AB + BC

ALL THE STEPS:

3 X + 3 = - 1 + 2 X + 11

3 X + 3 = 2 X + 10

3 X + ( - 2 X ) + 3 = 2 X + ( - 2 X ) + 10

X + 3 = 10

X + 3 + ( - 3 ) = 10 + ( - 3 )

X = 7

5 0
3 years ago
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John consistently saves
bagirrra123 [75]

Answer:

7789 i think this is the answer

Step-by-step explanation:

6 0
3 years ago
I need help with trigonometry <br> Again..
tigry1 [53]

Answer: C. - √2

Step-by-step explanation:

<u>Given requirements from the question</u>

Find the exact value of sec 135°

<u>Convert into common trigonometric expression</u>

sec = secant

secx = 1 / cosx

Therefore, sec 135° = 1 / (cos 135°)

<u>Find the reference angle</u>

135° is quite a complicated angle, but it is possible to simplify it by finding its reference angle.

Since 135° is in the second quadrant, its reference angle will be

                                         180° - 135° = 45°

However, we need to consider the positive and negative.

In a coordinate plane, the clue is (A S T C), which corresponds to the positive values in each quadrant. In the QI, "All" are positive. In the QII, sine is positive. In the QIII, the tangent is positive. In QIV, cosine is positive.

Therefore, when the value of cosine is in QII, it is negative.

The reference angle = - (1 / cos 45°)

<u>Determine the final value</u>

Given that the reference angle = - (1 / cos 45°)

cos 45° = 1 / √2

Therefore:

sec 135° = - (1 / cos 45°) = - (1 / (1 / √2)) = \boxed{-\sqrt{2} }

Hope this helps!! :)

Please let me know if you have any questions

5 0
2 years ago
Over what interval is the quadratic function decreasing?
frosja888 [35]

The interval over which the given quadratic equation decreases is:  x ∈ (5, ∞).

<h3>How to find the interval of quadratic functions?</h3>

Usually a quadratic graph function decreases either when moving from left to right or moving downwards.

In the given graph, we can see that the coordinate of the vertex is (5, 4) after which the curve goes in the downward direction.

Thus, for the values of x greater than 5, the function decreases and so we conclude that the interval in which the quadratic equation decreases is: (5, ∞).

Read more about Quadratic functions at: brainly.com/question/18030755

#SPJ1

6 0
2 years ago
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